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How many diagonals can be drawn from any vertex of a 20-sided polygon?
Wiki User
∙ 11y ago
It is 18 diagonals
Wiki User
∙ 11y ago
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How many diagonals can you drawn from one vertex in a 35 sided polygon?
A diagonal of a polygon is a segment drawn from one vertex to another non-adjacent vertex in a polygon. This leaves 32 diagonals that can be drawn from one vertex in a 35 sided polygon.
If in a 54 sided polygon all possible diagonals are drawn from one vertex they divide the interior of the polygon into how many regions?
In a 54-sided polygon, 53 possible diagonals can be drawn from one vertex to another. These diagonals will not intersect. Therefore, the interior will be divided into 54 regions by the 53 diagonals plus the two sides of the original polygon that adjoin the vertex from which the diagonals are drawn.
What statement can you make about the number of diagonals that can be drawn from one vertex in a polygon?
Number of sides minus two equals number of diagonals drawn from one vertex.
How many diagonals can be drawn from a five sided vertex polygon?
5
How many diagonals can be drawn from any vertex of a 20 sided polygon?
17
How many triangles will be formed in 100 sided polygon if the diagonals are drawn from a single vertex?
98
How many diagonals can be drawn from one vertex of a 7-sided polygon?
7-3 = 4
How many diagonal can be drawn from a regular hexagon from one vertex?
5 diagonals * * * * * That is not correct since two of these would be lines joining the vertex to adjacent vertices (one on either side). These are sides of the polygon, not diagonals. The number of diagonals from any vertex of a polygon with n sides is n-3.
How many diagonals can be drawn from one vertex of a polygon of 50 sides?
47 sides. Take a vertex of an n-sided polygon. There are n-1 other vertices. It is already joined to its 2 neighbours, leaving n-3 other vertices not connected to it. Thus n-3 diagonals can be drawn in from each vertex. For n=50, n-3 = 50-3 = 47 diagonals can be drawn from each vertex. The total number of diagonals in an n-sided polygon would imply n-3 diagonals from each of the n vertices giving n(n-3). However, the diagonal from vertex A to C would be counted twice, once for vertex A and again for vertex C, thus there are half this number of diagonals, namely: number of diagonals in an n-sided polygon = n(n-3)/2.
What can you say about the relationship of the number of diagonals that can be drawn from each vertex of a polygon?
The formula for the number of diagonals is: 0.5*(n^2-3n) whereas 'n' is the number of sides of the polygon
How many diagonals can be drawn from a vertex of an n gon?
n-3 diagonals. Of the n vertices of the polygon, you cannot draw diagonals to the two adjacent vertices since these are sides of the polygon and so not diagonals. And you cannot draw a diagonal from a vertex to itself. So those are three vertices that are ruled out, leaving n-3.
What is the number of diagonals that can be drawn from one vertex in a convex polygon that has n vertices?
N-2 according to yahoo answers
