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8 / 7 in long division is however many 7s go into 8. so there's 1x 7 in 8 with 1 remainder. For this example, assume every number beyond is a 10, multiplied by the remainder. so, it'd be 7s into 10, which is 1 again. Then 7s into 30, which is 4. Then 7s into 20, which is 2. Then 7s into 60, which 8. Then 7s into 40, which is 5. Then 7s into 50, which is 7. And this is a reoccuring number, making it 1.142857142857 and so on.
There are two 7s in the number. Which one do you mean by the 7?
To find how many 7s are in 93, you can divide 93 by 7. When you do this calculation, 93 ÷ 7 equals approximately 13.29. This means there are 13 full 7s in 93, with a remainder.
100
18/7
8 / 7 in long division is however many 7s go into 8. so there's 1x 7 in 8 with 1 remainder. For this example, assume every number beyond is a 10, multiplied by the remainder. so, it'd be 7s into 10, which is 1 again. Then 7s into 30, which is 4. Then 7s into 20, which is 2. Then 7s into 60, which 8. Then 7s into 40, which is 5. Then 7s into 50, which is 7. And this is a reoccuring number, making it 1.142857142857 and so on.
There are two 7s in the number. Which one do you mean by the 7?
To find how many 7s are in 93, you can divide 93 by 7. When you do this calculation, 93 ÷ 7 equals approximately 13.29. This means there are 13 full 7s in 93, with a remainder.
there is one 7 for every 10 numbers. There are 20 sets of ten going up to 201, so 20 7s there. There is also the 70s, and 170s, which each have 10 7s, making 20 more 7s. In total, the number 7 appears 40 times from 7 to 201.
100
18/7
7, remainder 2
210 ÷ 7 = 30
There are: 777/7 = 111
The current number 7 is Michael Owen.
To find how many times 7 fits into 31, you can divide 31 by 7. Doing the calculation, 31 ÷ 7 equals approximately 4.43. This means there are 4 whole 7s in 31, with a remainder. Thus, 31 contains four 7s.
In the number 777, there are three occurrences of the digit 7. Each digit in 777 is a 7, so you can count them individually: 7, 7, and 7. Therefore, the answer is three 7s.