9
None is divisible by all those.
There are 9 numbers evenly divisible by 10 : 10, 20, 30, 40, 50, 60, 70, 80, and 90
There are 300.
24, 30 and 36.
9
None is divisible by all those.
Oh, isn't that a happy little question! To find the two-digit numbers divisible by 3, we start by finding the first two-digit number divisible by 3, which is 12. Then, we find the last two-digit number divisible by 3, which is 99. Now, we can count how many numbers there are between 12 and 99 that are divisible by 3.
There are 9 numbers evenly divisible by 10 : 10, 20, 30, 40, 50, 60, 70, 80, and 90
There are 300.
24, 30 and 36.
All real numbers are divisible by four. However, no numbers with decimal extensions are evenly divisible by four. The only numbers evenly divisible by four between 30 and 39 are 32 and 36. Otherwise, including decimals, there would be an infinite number of rational numbers between those limits divisible by four, and infinitely more than that if the real numbers are included (numbers that cannot be represented by terminating or repeating continued decimal expansions).
The only one is 36.
Starting at 12 and ending at 99, there are 30 two-digit numbers divisible by three.
985 / 2 = 492 985 / 3 = 328 985 / 5 = 197 in all cases just round down to get your answer. if you mean how many numbers are divisible by all 3 numbers at the same time: 2x3x5 = 30 985 / 30 = 32
The only numbers between 30 and 50 that could be prime are 31, 33, 35, 37, 39, 41, 43, 45, 47, 49 because all other numbers are even. 35 and 45 cannot be prime because they are divisible by 5. 33 is divisible by 3, so it is not prime, and 49 is divisible by 7, so it is not prime. That leaves numbers 31, 37, 41, 43, 47, so there are five prime numbers between 30 and 50.
They are: 15 30 45 60 75 and 90 which makes six of them