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How many 2 digit numbers are divisible by 5 and 6?
If n is divisible by both 5 and 6, then it should be divisible by 30 (5 * 6). Considering you are asking for only two-digit numbers, the answer(s) would be 30, 60, and 90. So, three numbers.
How many numbers between 30 and 40 are divisible by 4 5 and 9?
None is divisible by all those.
How many natural numbers between 1 and 30 are divisible by three?
9
How many five digit numbers ae exit such that their product is 400?
30
What numbers are divisible with 30?
30,60,90,120,150,180,210,240,270,300,330,360,390,420,450,480,510,540,570, 600,630,660,690,720,750,780,810,840,900,930,960,990,1020,1050,1080,1110
How many 2 digit numbers are divisible by 3?
Starting at 12 and ending at 99, there are 30 two-digit numbers divisible by three.
How many two - digit numbers are divisible by 3?
Oh, isn't that a happy little question! To find the two-digit numbers divisible by 3, we start by finding the first two-digit number divisible by 3, which is 12. Then, we find the last two-digit number divisible by 3, which is 99. Now, we can count how many numbers there are between 12 and 99 that are divisible by 3.
How many 2 digit numbers are divisible by 5 and 6?
If n is divisible by both 5 and 6, then it should be divisible by 30 (5 * 6). Considering you are asking for only two-digit numbers, the answer(s) would be 30, 60, and 90. So, three numbers.
How many 5 digit combos in 30 numbers?
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
How many two digit numbers divisible by neither 3 nor 5?
48.The first two digit number is 10, the last two digit number is 99, so there are 99 - 10 + 1 = 90 two digit numbers→ 10 ÷ 3 = 31/3 → first two digit number divisible by 3 is 4 x 3 = 12→ 99 ÷ 3 = 33 → last two digit number divisible by 3 is 33 x 3 = 99→ 33 - 4 + 1 = 30 two digit numbers divisible by 3→ 10 ÷ 5 = 2 → first two digit number divisible by 5 is 2 x 5 = 10→ 99 ÷ 5 = 194/5 → last two digit number divisible by 5 is 19 x 5 = 95→ 19 - 2 + 1 = 18 two digit numbers divisible by 5→ 30 + 18 = 48 two digit numbers divisible by 3 or 5 OR BOTH.The numbers divisible by both are multiples of their lowest common multiple: lcm(3, 5) = 15, and have been counted twice, so need to be subtracted from the total→ 10 ÷ 15 = 010/15 → first two digit number divisible by 15 is 1 x 15 = 15→ 99 ÷ 15 = 69/15 → last two digit number divisible by 15 is 6 x 15 = 90→ 6 - 1 + 1 = 6 two digit numbers divisible by 15 (the lcm of 3 and 5)→ 48 - 6 = 42 two digit numbers divisible by 3 or 5.→ 90 - 42 = 48 two digit numbers divisible by neither 3 nor 5.
What are twin prime numbers divisible by 5?
there aren't any as otherwise they wouldn't be prime numbers
How many three digit numbers are there that are multiples of 30?
29 of them.
List of numbers divisible by 5?
All the numbers divisible by 5 are the numbers ending with the digit 5 or 0. The first ten examples are: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50
How many 2 digit numbers have factors of 2 and 5?
Two digit numbers are in the range: 10 to 99. Having both 2 & 5 as factors, means the number will be divisible by 10, so there are nine numbers that fit this:{10, 20, 30, 40, 50, 60, 70, 80, 90}
How many numbers between 30 and 40 are divisible by 4 5 and 9?
None is divisible by all those.
How many natural numbers between 1 and 30 are divisible by three?
9
How many five digit numbers ae exit such that their product is 400?
30
