6
Probably infinite. The smallest is known as Ramanujan's number, 1729 using cubes of 1 and 12, and of 9 and10. Read more about the genius Ramanujan in Wikipaedia.
The cube root of 5000 is approx 17.1 So the numbers 1 to 17 have cubes which are smaller than 5000 that is, there are 17 such numbers.
36
The perfect cubes among the first 1000 natural numbers are the cubes of the integers from 1 to 10, since (10^3 = 1000). These integers are 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10. Therefore, there are 10 perfect cubes in the first 1000 natural numbers.
Each cube has 8 vertices. Therefore, for 6 cubes, you would multiply the number of vertices per cube by the number of cubes: 8 vertices/cube × 6 cubes = 48 vertices. So, there are 48 vertices on 6 cubes.
There are 12 squares on 2 cubes
Probably infinite. The smallest is known as Ramanujan's number, 1729 using cubes of 1 and 12, and of 9 and10. Read more about the genius Ramanujan in Wikipaedia.
The cube root of 5000 is approx 17.1 So the numbers 1 to 17 have cubes which are smaller than 5000 that is, there are 17 such numbers.
If you have got enough cubes, as many as you like.
36
The perfect cubes among the first 1000 natural numbers are the cubes of the integers from 1 to 10, since (10^3 = 1000). These integers are 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10. Therefore, there are 10 perfect cubes in the first 1000 natural numbers.
Each cube has 8 vertices. Therefore, for 6 cubes, you would multiply the number of vertices per cube by the number of cubes: 8 vertices/cube × 6 cubes = 48 vertices. So, there are 48 vertices on 6 cubes.
six faces
A regular can of 12oz coke has sugar equal to nearly 10 standard sugar cubes. see this website: http://www.sugarstacks.com/beverages.htm
Well one has eight vertices then you just multiply eight by whatever number of cubes you have!
If you have 5 distinct cubes, the number of arrangements can be calculated using the factorial of the number of cubes. Thus, the total arrangements would be 5! (5 factorial), which equals 120. If the cubes are identical, there would be only 1 arrangement.
6