21, 28, 35, 42, 49, 56
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17 of them.
They are the numbers divisible by 2 with a remainder of 1
600 ÷ 17 = 355/17 2000 ÷ 17 = 11711/17 → 117 - 35 = 82 integers between 600 and 2000 are divisible by 17.
There will be (200-100)/2+1 = 51 numbers divisible by 2.There will be Floor[(200 - 100)/3] = 33 numbers divisible by 3.Multiples of 6 from the 17th through the 33rd will be counted twice by the sum of these numbers (51+33). There are 17 of them.That means the count of numbers you are interested in is 51+33-17 = 67.
There are infinitely many numbers between 9 and 17. For example, 10 or 13.568There are infinitely many numbers between 9 and 17. For example, 10 or 13.568There are infinitely many numbers between 9 and 17. For example, 10 or 13.568There are infinitely many numbers between 9 and 17. For example, 10 or 13.568