There are 5 numbers between 17 and 61 that are divisible by 8. They are 24, 32, 40, 48, and 56.
17 they are: 0,6,12,18,24,30,36,42,48,54,60,66,72,78,84,90 & 96
150 ÷ 9 = 16 r 6 → the first natural number between 150 and 300 divisible by 9 is 9 × 17 (=154)300 ÷ 9 = 33 r 3 → the last natural number between 150 and 300 divisible by 9 is 9 × 33 (=297)→ there are 33 - 17 + 1 = 17 natural numbers between 150 and 300 divisible by 9.
There are 67 numbers between 100 and 500 divisible by 6. The first number greater than 100 divisible by 6: 100 ÷ 6 = 16 r 4 → first number divisible by 6 is 6 × 17 = 102 Last number less than 500 divisible by 6: 500 ÷ 6 = 83 r 2 → last number divisible by 6 is 6 × 83 = 498 → all multiples of 6 between 17 × 6 and 83 × 6 inclusive are the numbers between 100 and 500 that are divisible by 6. → there are 83 - 17 + 1 = 67 such numbers.
All multiples of 17 are divisible by 17. There is an infinite number of multiples of 17.
Well, isn't that a happy little question! To find out how many three-digit numbers are divisible by 17, we can simply divide the largest three-digit number by 17 and see how many whole numbers we get. By doing this, we can see that there are 47 three-digit numbers that are divisible by 17. Just imagine all those numbers lining up like little trees in a peaceful forest!
To find the numbers between 50 and 100 that are divisible by 3, we can use the formula for finding the number of integers divisible by a certain number within a range. The formula is (largest number - smallest number) / divisor + 1. In this case, the largest number is 99, the smallest number is 51, and the divisor is 3. Plugging these values into the formula, we get (99 - 51) / 3 + 1 = 16. Therefore, there are 16 numbers between 50 and 100 that are divisible by 3.
17 of them.
17 of them.
17 they are: 0,6,12,18,24,30,36,42,48,54,60,66,72,78,84,90 & 96
150 ÷ 9 = 16 r 6 → the first natural number between 150 and 300 divisible by 9 is 9 × 17 (=154)300 ÷ 9 = 33 r 3 → the last natural number between 150 and 300 divisible by 9 is 9 × 33 (=297)→ there are 33 - 17 + 1 = 17 natural numbers between 150 and 300 divisible by 9.
They are the numbers divisible by 2 with a remainder of 1
21, 28, 35, 42, 49, 56
There are 67 numbers between 100 and 500 divisible by 6. The first number greater than 100 divisible by 6: 100 ÷ 6 = 16 r 4 → first number divisible by 6 is 6 × 17 = 102 Last number less than 500 divisible by 6: 500 ÷ 6 = 83 r 2 → last number divisible by 6 is 6 × 83 = 498 → all multiples of 6 between 17 × 6 and 83 × 6 inclusive are the numbers between 100 and 500 that are divisible by 6. → there are 83 - 17 + 1 = 67 such numbers.
All multiples of 17 are divisible by 17. There is an infinite number of multiples of 17.
Well, isn't that a happy little question! To find out how many three-digit numbers are divisible by 17, we can simply divide the largest three-digit number by 17 and see how many whole numbers we get. By doing this, we can see that there are 47 three-digit numbers that are divisible by 17. Just imagine all those numbers lining up like little trees in a peaceful forest!
17 odd numbers.
Well, darling, you simply divide the range by the divisor and add 1 if the starting number is divisible by the divisor. In this case, you divide 1000 by 6 and subtract the result of dividing 100 by 6. So, (1000/6) - (100/6) + 1 = 166 - 16 + 1 = 151 numbers between 100 and 1000 are divisible by 6. Hope that tickles your fancy!