The prime factorization of 56 is 2, 2, 2, and 7, so there there are two prime numbers, 2 and 7, that can evenly go into 56.
other than 1 and itself there are six other numbers that go into 56 2, 4, 7, 8, 14, 28
56=2x2x2x7
The whole numbers that go into 56 are: 1, 2, 4, 7. 8, 14, 28, 56
8C3 = 56 of them
The prime factorization of 56 is 2, 2, 2, and 7, so there there are two prime numbers, 2 and 7, that can evenly go into 56.
other than 1 and itself there are six other numbers that go into 56 2, 4, 7, 8, 14, 28
56=2x2x2x7
1, 2, 4, 7, 8, 14, 28, 56
1,2,4,7,8,14,28,56
The whole numbers that go into 56 are: 1, 2, 4, 7. 8, 14, 28, 56
Two of them.
8C3 = 56 of them
multiples of 56
Any multiple of 56.
1 and 7
Assuming 9 numbers chosen from 56, with no repetition allowed, there are 7575968400 possible combinations.