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-- Each one must have either 3 or 4 digits.

-- The first digit must be the 6, the 7, or the 8 = 3 choices. For each of those ...

-- The second digit can be any of the 3 unused ones = 3 choices. For each of those ...

-- The third digit can be either of the 2 unused ones = 2 choices. For each of those ...

-- The fourth digit can be either the unused one or else blank = 2 choices.

Total number of choices = 3 x 3 x 2 x 2 = only 36 possibilities. I am surprised.

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