There are: 7C6 = 7
8
There is 1 combination of all ten numbers, 10 combinations of one number and of nine numbers, 45 combinations of two or eight numbers, 120 combinations of three or seven numbers, 210 combinations of four or six numbers and 252 combinations of five numbers. That is 1023 = 210 - 1 in total.
There are 8C6 = 8*7/(2*1) = 28 combinations.
9!/6!, if the six different orders of any 3 digits are considered distinct combinations.
There are: 7C6 = 7
8
Just 1.
Assuming that the six numbers are different, the answer is 15.
There is 1 combination of all ten numbers, 10 combinations of one number and of nine numbers, 45 combinations of two or eight numbers, 120 combinations of three or seven numbers, 210 combinations of four or six numbers and 252 combinations of five numbers. That is 1023 = 210 - 1 in total.
If the numbers are allowed to repeat, then there are six to the fourth power possible combinations, or 1296. If they are not allowed to repeat then there are only 360 combinations.
There are 8C6 = 8*7/(2*1) = 28 combinations.
Six combinations: 123, 132, 213, 231, 312, 321
figure it out then tell me :)
There are 8!/[6!(8-6)!] = 8*7/2 = 28 - too many to list.
9!/6!, if the six different orders of any 3 digits are considered distinct combinations.
If you use each number once, there are six combinations.