45, of which 9 are of the form nnn.
The options are (a) 121 (b)117 (c) 112 (d) 115 (e) 105.
It's out of those answers. If you're like me and retrieved this question off the Australian Maths Competition than you probably already know the options. Surprisingly this question stumped me. However I will try and work it out.
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Multiplying by multi-digit numbers is similar to multiplying by two-digit numbers in that both processes involve breaking down the numbers into place values and multiplying each digit by each digit in the other number. The key similarity lies in the application of the distributive property, where each digit in one number is multiplied by each digit in the other number, and then the products are added together to get the final result. This process is consistent whether you are multiplying by a two-digit number or a multi-digit number.
There are 16 square numbers between 1 and 300: 2 to 17 inclusive. There is no square root of these numbers: only of their sum or product or average or some other operation.
That would be the numbers in the form "32x" (where "x" can be any digit). In other words, ten numbers.
No, there are composite numbers that end in every other digit.
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Yes. By 1 digit, 2 digit and some even by other 3 digit numbers.
Multiplying by multi-digit numbers is similar to multiplying by two-digit numbers in that both processes involve breaking down the numbers into place values and multiplying each digit by each digit in the other number. The key similarity lies in the application of the distributive property, where each digit in one number is multiplied by each digit in the other number, and then the products are added together to get the final result. This process is consistent whether you are multiplying by a two-digit number or a multi-digit number.
There are 16 square numbers between 1 and 300: 2 to 17 inclusive. There is no square root of these numbers: only of their sum or product or average or some other operation.
That would be the numbers in the form "32x" (where "x" can be any digit). In other words, ten numbers.
Eight (8) of them do.They are1221243642486384 .
No, there are composite numbers that end in every other digit.
9,000,000 if there are no other requirements.
Yes.
Composite numbers are integers greater than 1 that can be divided evenly by numbers other than 1 and themselves. In the case of numbers up to 100, the unit's digit refers to the digit in the ones place. The claim that composite numbers up to 100 have 1 as their unit's digit is incorrect, as composite numbers can have any digit in the ones place depending on their factors.
The 3-digit counting numbers are 100 through 999 = 900 numbers.Half them are multiples of 2 (even numbers).The other half are not . . . 450 of them.
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