add numbers below to each number at the top
Numbers that can easily divide into each other without any remainders. :)
Divide the numbers that are diagonal from each other, but there are times when this does not work.
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
To multiply two digit numbers, multiply each place value of a factor by each place value digit and add the results.
It would help to know which digit. 0 appears in 9 numbers and each of the others in 18 numbers.
There are four of each.
All decimal numbers are simply a way of representing numbers in such a way that the place value of each digit is ten times that of the digit to its right.
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
The first digit can by selectd in one of two ways, since a number starting with zero would not be a 5-digit number. After that, each of the other four digits can be selected in 3 ways. So the number of 5-digit numbers is 2*34 = 162
93 and 42
It doesn't always. It's true only if the 4-digit numbers are mirror images of each other.