23 or 8 outcomes. In any experiment with two outcomes, if you do the experiment n times there are 2n outcomes.
This about each time you roll the coin have two possible outcomes, H or T.
So if you roll it 2 times, you have 4 possible outcomes. HH, HT, TH or TT.
Do it one more time and you have 8 outcomes.
HHH, HHT, HTH, THH
TTT TTH THT HTT
Notice there are
1 outcome with 3 heads, 1 with 3 tails
3 with two heads
3 with two tails
This pattern follow the binomial theorem.
The coefficients of the binomial (H+T)3
are 1 3 3 1. The same numbers as we have above!
When flipping 3 coins, each coin has 2 possible outcomes: heads (H) or tails (T). Therefore, the total number of outcomes is calculated as (2^3), which equals 8. The possible outcomes are: HHH, HHT, HTH, HTT, THH, THT, TTH, and TTT. Thus, there are 8 different outcomes from flipping 3 coins.
The probability of rolling a 2 or a 3 on a standard six-sided die can be calculated by considering the favorable outcomes. There are two favorable outcomes (rolling a 2 or a 3) out of a total of six possible outcomes. Therefore, the probability is 2 out of 6, which simplifies to 1/3, or approximately 0.33 (33.3%).
3 of them.
When rolling a standard six-sided die, there are six possible outcomes: 1, 2, 3, 4, 5, and 6. The probability of rolling a 6 is the number of favorable outcomes (1, which is rolling a 6) divided by the total number of outcomes (6). Therefore, the probability of rolling a 6 is 1/6 or approximately 16.67%.
The simple sample space for the event of first rolling a die and then shooting a basket consists of the outcomes from both actions. There are 6 possible outcomes when rolling a die (1, 2, 3, 4, 5, or 6), and if we assume there are 2 possible outcomes for shooting a basket (making it or missing it), we multiply the outcomes: 6 (from the die) × 2 (from the basket) = 12 total outcomes. Thus, there are 12 possible outcomes in the combined simple space.
9
When flipping 3 coins, each coin has 2 possible outcomes: heads (H) or tails (T). Therefore, the total number of outcomes is calculated as (2^3), which equals 8. The possible outcomes are: HHH, HHT, HTH, HTT, THH, THT, TTH, and TTT. Thus, there are 8 different outcomes from flipping 3 coins.
6 x 6 x 6 = 216
-- 8 possibilities if the coins are different colors. -- Only 4 possibilities if you can't tell the coins apart.
Three: they are 3, 5 and 6.
There are eight possible outcomes: HHH, HHT, HTT, HTH, THT, TTT, TTH, THH.
6 outcomes each roll, 3 rolls. 6*6*6 = 216.
3 of them.
there's 1/3 chance of getting an even number in a die, hon
Use Pascal's Triangle Answer is 14641 different outcomes. - - - - 1 - - - 1 - 1 - - 1 - 2 - 1 - 1 - 3 - 3 - 1 1 - 4 - 6 - 4 - 1
Probability = (number of successful outcomes) / (number of possible outcomes)Possible outcomes: 6Successful outcomes: 1Probability = 1/6 = 16 and 2/3 percent.
If each coin is a different color, then there are 32 possible outcomes. If you can't tell the difference between the coins, and you're just counting the number of heads and tails, then there are 6 possible outcomes: 5 heads 4 heads 3 heads 2 heads 1 heads all tails