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If joe sam and mary each flip a coin how many possible outcomes are there?
If you can identify the outcomes with who flipped each coin: eg Joe and Mary = Heads, Sam = Tails, then 23 = 8. Otherwise, 4.
Possible outcomes of tossing a coin?
Heads or tails; each have a probability of 0.5 (assuming a fair coin).
How is selecting one marble from each of 2 bags and tossing 2 coins similar?
It is not. There are only two possible outcomes for each toss of a coin whereas the number of possible outcomes when selecting a marble from a bag will depend on the numbers of distinct marbles in each bag. The coin toss generates a binomial distribution the marbles experiment is multinomial.
If you toss a penny a nickel and a quarter and a dime how many possible outcomes?
Each coin has two possible outcomes, either Heads or Tails. Then the number of outcomes when all 4 coins are tossed is, 2 x 2 x 2 x 2 = 16.
How many possible outcomes would there be if eleven coins were tossed at once?
The answer depends on what the outcome comprises.If the outcome is simply a count of H and T, then there are 12 outcomes: 0H, 1H, 2H, ... 10H and 11H (with the corresponding number of T in each case).If the result for each coin is recorded individually, there are 211 = 2048 possible outcomes.There are many other results that can be defined, and the number of possible outcomes will vary according to the definitions.The answer depends on what the outcome comprises.If the outcome is simply a count of H and T, then there are 12 outcomes: 0H, 1H, 2H, ... 10H and 11H (with the corresponding number of T in each case).If the result for each coin is recorded individually, there are 211 = 2048 possible outcomes.There are many other results that can be defined, and the number of possible outcomes will vary according to the definitions.The answer depends on what the outcome comprises.If the outcome is simply a count of H and T, then there are 12 outcomes: 0H, 1H, 2H, ... 10H and 11H (with the corresponding number of T in each case).If the result for each coin is recorded individually, there are 211 = 2048 possible outcomes.There are many other results that can be defined, and the number of possible outcomes will vary according to the definitions.The answer depends on what the outcome comprises.If the outcome is simply a count of H and T, then there are 12 outcomes: 0H, 1H, 2H, ... 10H and 11H (with the corresponding number of T in each case).If the result for each coin is recorded individually, there are 211 = 2048 possible outcomes.There are many other results that can be defined, and the number of possible outcomes will vary according to the definitions.
How many possible outcomes if each coin is flipped once?
We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
If there are three coins and each is flipped once how many possible outcomes are there?
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
If joe sam and mary each flip a coin how many possible outcomes are there?
If you can identify the outcomes with who flipped each coin: eg Joe and Mary = Heads, Sam = Tails, then 23 = 8. Otherwise, 4.
Two coins are flipped and a die is rolled how many possible outcomes are there?
Each coin can land in two ways.The die has 6 possible outcomes.So there are 2 x 2 x 6 = 24 possible outcomes for the whole experiment.Note that I am assuming the coins can be told apart - say the first coin and 2nd coin and that H and then T is different that T and then H. If not, then there are only be three outcomes for the coins-- 2 heads, 1 head or no heads and the total number of outcomes would be 3 X 6 = 18.
How many possible outcomes are there when flipping a coin 11 times?
Two possible outcomes for each flip. 2,048 possible histories of 11 flips.
Possible outcomes of tossing a coin?
Heads or tails; each have a probability of 0.5 (assuming a fair coin).
What is the probability of getting at least 2 heads in three flips of a fair coin?
In three flips of a fair coin, there are a total of 8 possible outcomes: T, T, T; T, T, H; T, H, T; T, H, H; H, H, H; H, H, T; H, T, H; H, T, T Of the possible outcomes, four of them (half) contain at least two heads, as can be seen by inspection. Note: In flipping a coin, there are two possible outcomes at each flipping event. The number of possible outcomes expands as a function of the number of times the coin is flipped. One flip, two possible outcomes. Two flips, four possible outcomes. Three flips, eight possible outcomes. Four flips, sixteen possible outcomes. It appears that the number of possible outcomes is a power of the number of possible outcomes, which is two. 21 = 2, 22 = 4, 23 = 8, 24 = 16, .... Looks like a pattern developing there. Welcome to this variant of permutations.
If you toss a penny a nickel and a quarter how many possible outcomes?
There are technically 8 possible outcomes if you are talking about the side of the coin it lands on. Each coin has 2 possible outcomes (landing on heads and landing on tails). To figure out the number of outcomes for all the coins you multiply the outcomes for all of the coins together: 2 X 2 X 2= 8.
If SamJoe and Debbie each flip a coin how many possible outcomes are there?
I am guessing SamJoe, means SAM and JOE not one person, so three people flip a coin, we have two outcomes each times, so 23= 8 possible outcomes. If you had n people, there would be 2n outcomes. For example, if two people flip there are 4 outcomes HH TT HT or TH
A fair coin is tossed 3 times how many possible outcomes are there?
Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8
How is selecting one marble from each of 2 bags and tossing 2 coins similar?
It is not. There are only two possible outcomes for each toss of a coin whereas the number of possible outcomes when selecting a marble from a bag will depend on the numbers of distinct marbles in each bag. The coin toss generates a binomial distribution the marbles experiment is multinomial.
How many possible outcomes if you toss a coin four times?
When you toss a coin four times, each toss has 2 possible outcomes: heads or tails. To find the total number of outcomes, you multiply the number of outcomes for each toss together. In this case, it would be 2 x 2 x 2 x 2 = 16 possible outcomes.
