they would be of the format XYX
where X varies from 1 to 9
and Y varies from 0 to 9 for each value of X.
for a total of 9 * 10 combinations = 90
*This Assumes that you wanted to include 999 as one of your answers How ever it could be argued (correctly) that it is not between 100 and 999*
There is: 101,111,121,131,141,151,161,171,181,191 202,212,222,etc... 999 There are 90 palindromic 3 digit numbers
There are 900 digits between the numbers 100 and 999. This range includes all the three-digit numbers from 100 to 999, which is calculated by subtracting 100 from 999 and adding 1 (to include both endpoints): 999 - 100 + 1 = 900.
1001, 1111
180
it too long but its between 100 000 and 999 999 examples: 124 132 556 318 582 782 123 126 436 419 665 876 258 965 875 785 256 487 756 356
Between 100 and 999 there are 448.
There are 30 multiples of 30 between 100 and 999.
Including 100 and 999 themselves, 900. If you don't count 100 and 999, there are 898.
There is: 101,111,121,131,141,151,161,171,181,191 202,212,222,etc... 999 There are 90 palindromic 3 digit numbers
There are 900 digits between the numbers 100 and 999. This range includes all the three-digit numbers from 100 to 999, which is calculated by subtracting 100 from 999 and adding 1 (to include both endpoints): 999 - 100 + 1 = 900.
There are 280 of them.
450
Including 100 and 999 themselves, 900. If you don't count 100 and 999, there are 898.
1001, 1111
180
450450450450
it too long but its between 100 000 and 999 999 examples: 124 132 556 318 582 782 123 126 436 419 665 876 258 965 875 785 256 487 756 356