Assuming that you have to use all 4 of the letters with no repeats there are 4! or 4 factorial. Because you are asking how many ways can I arrange n objects if I use all n of them, the number of permutations is n!. To calculate factorials, you multiply the number by every integer before it until you reach 1. So 4! equals 4 X 3 X 2 X1 or 24. So there are 24 ways you can arrange the letters G,X,K, and T.
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The word "DECAGON" has 7 letters, with the letter "A" appearing once, "C" appearing once, "D" appearing once, "E" appearing once, "G" appearing once, "N" appearing once, and "O" appearing once. To find the number of different 4-letter permutations, we need to consider combinations of these letters. Since all letters are unique, the number of 4-letter permutations is calculated using the formula for permutations of n distinct objects taken r at a time: ( P(n, r) = \frac{n!}{(n-r)!} ). Here, ( n = 7 ) and ( r = 4 ), so the number of permutations is ( P(7, 4) = \frac{7!}{(7-4)!} = \frac{7!}{3!} = 7 \times 6 \times 5 \times 4 = 840 ). Thus, there are 840 different 4-letter permutations that can be formed from the letters in "DECAGON."
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Capital letters or big letters. ex. A G L U E The opposite of lowercase letters. (a g l u e )
g
Four. F, G, J, L