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Five intersecting lines can have a maximum of 10 points of intersection, assuming that no two lines are parallel and no three lines intersect at the same point. Each pair of lines can intersect at one unique point, and the number of ways to choose 2 lines from 5 is given by the combination formula ( \binom{5}{2} = 10 ). Therefore, with optimal conditions, the maximum number of intersection points is 10.

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2w ago

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How many intersecting points occur when 4 parallel lines are perpendicular to 5 other lines?

There are 20 common points.


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If no pair of lines is parallel and if each pairwise intersection is distinct, there will be 10 points of intersection.


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Here are some: They can be (1) coincident, (2) intersecting at one point, (3) coplanar but non-intersecting (ie parallel), (4) non-coplanar, non-parallel and non-intersecting (eg paths of a rail line and of an elevated road going over it - from above, they may appear to intersect but they do not), (5) intersecting at two points (eg longitudes on the earth). etc.


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when a pair of angles/numbers have 1 of the same numbers (for example: 4,3,5,6 and 1,2,3,5,4 have intersecting numbers (4,3, and 5) and also points (4,5) and (4,6) Haver them too (because 4 stands for the 'x' the if you were to plot that on a graph, the points would intersct one another)


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The greatest number of intersection points with just four lines is 6.