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Three aces and two eights is a full house. Three Aces and two nines would win. As would three aces and two kickers 10 or higher.
Approximately 2%
P(x=4) ≈ 0.00001847 or about 1 in 54 145The probability of selecting 4 aces while playing poker with six people is:P(x=4) = 5C4 ∙ 4!/[52!/(52-30)!] ∙ (52-4)!/(52-30)!= 5C4 ∙ 4!(52-4)!/52! ≈ 1.846892603... x 10-5 ≈ 0.00001847which is about 1 in 54 145.
4 aces
Well, honey, there are four aces in a standard 52-card deck. So, if you're trying to impress someone with your card knowledge, just remember that little nugget of information. And if you're playing poker, those aces might just be your ticket to winning big. Good luck, sweet cheeks!