answersLogoWhite

0


Best Answer

2

User Avatar

Wiki User

12y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many poker hands contain exactly 2 Aces?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What are poker bullets?

a pair of aces.


When you play poker cards game and you have straight Aces in your hand what that mean?

suited aces


Does five aces beat a straight in poker?

It depends on the type of poker game being played.In a game where aces are low (they are equivalent to the number 1). In that case yes, a pair of fives beats a pair of aces.In a game where aces are high, then no, the pair of aces definitely wins. A pair of aces is the highest single pair you can get in the game of poker, before getting two pair or higher.Both of these types of games are played in poker.


The probability of being dealt 4 aces in a 5 card poker hand?

Poker hands are combinations of cards (when the order does not matter, but each object can be chosen only once.)The number 52C5 of combinations of 52 cards taken 5 at a time is (52x51x50x49x48) / (5x4x3x2x1) = 2,598,960.The number of hands which contain 4 aces is 48 (the fifth card can be any of 48 other cards.)So there is 1 chance in (2,598,960 / 48) = 54,145 of being dealt 4 aces in a 5 card hand.The odds are 54,144 to 1 against. The probabilityis 1/54145 = (approx.) 0.000018469 or 0.0018469%.


Do 2 aces and two tens and a two beat 3 fives a 6 and a 8?

No. Three of a kind beats two pair in poker hands.


Password for nettimestari poker c4.aces?

INFINITY


Bullets at the poker table in a crossword puzzle?

Aces


4 aces in poker is called?

Four of a kind.


What is the probability of getting exactly three aces in a five-card poker hand dealt from an ordinary 52 card deck?

The probability of getting 3 aces in the order AAABB is; P(AAABB) = (4/52)∙(3/51)∙(2/50)∙(48/49)∙(47/48) = 0.0001736... There are 5C3 = 5!/(3!∙(5-3)!) = 10 different ways in which the aces can come out. So the probability of getting exactly three aces in a five card poker hand dealt from a 52 card deck is, P(3A) ~ 10∙(0.0001736) ~ 0.001736 ~ 0.1736%


What is the probability that a random selected poker hand contains exactly 3 aces given that it contains at least 2 aces?

To calculate the probability of a random selected poker hand containing exactly 3 aces given that it contains at least 2 aces, we first need to determine the total number of ways to choose a poker hand with at least 2 aces. This can be done by considering the different combinations of choosing 2, 3, or 4 aces from the 4 available in a standard deck of 52 cards. Once we have the total number of ways to choose at least 2 aces, we then calculate the number of ways to choose exactly 3 aces from the selected hand. Finally, we divide the number of ways to choose exactly 3 aces by the total number of ways to choose at least 2 aces to obtain the probability.


What are 'freerolls' in the game of poker?

A freeroll in the game of poker is a situation in which a player cannot win the hand and cannot lose the hand. An example of a freeroll hand is when a person has 2 aces and other person has 2 aces.


How many ace are in a deck?

A poker deck has four aces.