Three aces and two eights is a full house. Three Aces and two nines would win. As would three aces and two kickers 10 or higher.
Approximately 2%
P(x=4) ≈ 0.00001847 or about 1 in 54 145The probability of selecting 4 aces while playing poker with six people is:P(x=4) = 5C4 ∙ 4!/[52!/(52-30)!] ∙ (52-4)!/(52-30)!= 5C4 ∙ 4!(52-4)!/52! ≈ 1.846892603... x 10-5 ≈ 0.00001847which is about 1 in 54 145.
4 aces
4 kings and 4 aces
a pair of aces.
suited aces
It depends on the type of poker game being played.In a game where aces are low (they are equivalent to the number 1). In that case yes, a pair of fives beats a pair of aces.In a game where aces are high, then no, the pair of aces definitely wins. A pair of aces is the highest single pair you can get in the game of poker, before getting two pair or higher.Both of these types of games are played in poker.
No. Three of a kind beats two pair in poker hands.
Poker hands are combinations of cards (when the order does not matter, but each object can be chosen only once.)The number 52C5 of combinations of 52 cards taken 5 at a time is (52x51x50x49x48) / (5x4x3x2x1) = 2,598,960.The number of hands which contain 4 aces is 48 (the fifth card can be any of 48 other cards.)So there is 1 chance in (2,598,960 / 48) = 54,145 of being dealt 4 aces in a 5 card hand.The odds are 54,144 to 1 against. The probabilityis 1/54145 = (approx.) 0.000018469 or 0.0018469%.
INFINITY
Aces
Four of a kind.
The probability of getting 3 aces in the order AAABB is; P(AAABB) = (4/52)∙(3/51)∙(2/50)∙(48/49)∙(47/48) = 0.0001736... There are 5C3 = 5!/(3!∙(5-3)!) = 10 different ways in which the aces can come out. So the probability of getting exactly three aces in a five card poker hand dealt from a 52 card deck is, P(3A) ~ 10∙(0.0001736) ~ 0.001736 ~ 0.1736%
A freeroll in the game of poker is a situation in which a player cannot win the hand and cannot lose the hand. An example of a freeroll hand is when a person has 2 aces and other person has 2 aces.
A poker deck has four aces.
aces