To find the number of sides ( n ) of a polygon given the number of diagonals, we can use the formula for the number of diagonals in a polygon: ( D = \frac{n(n-3)}{2} ). Setting ( D = 1175 ), we get the equation ( n(n-3) = 2350 ). Solving the quadratic equation ( n^2 - 3n - 2350 = 0 ) using the quadratic formula yields ( n \approx 50 ). Thus, the polygon has 50 sides.
50*(50 - 3)/2 = 1175 diagonals.
It works out that a polygon with 1175 diagonals has 50 sides
Regular polygons. A square and rectangle will have congruent (equal length) diagonals.
no
It has 464 diagonals. I used n(n-3)/2. Works for all polygons.
The principal diagonals of all regular polygons.
It is not possible to answer the question since there are no polygons "following".
square and rectangle
rectangle
All regular polygons.
A cone does not have any diagonals in the traditional sense, as diagonals are defined in polygons. A cone has a circular base and a single vertex at the top, making it a three-dimensional shape rather than a polygon. Therefore, it does not possess diagonals like a polygon does.
A square, a rhombus and a kite all have perpendicular diagonals that intersect at right angles