To find the number of sides ( n ) of a polygon given the number of diagonals, we can use the formula for the number of diagonals in a polygon: ( D = \frac{n(n-3)}{2} ). Setting ( D = 1175 ), we get the equation ( n(n-3) = 2350 ). Solving the quadratic equation ( n^2 - 3n - 2350 = 0 ) using the quadratic formula yields ( n \approx 50 ). Thus, the polygon has 50 sides.
It works out that a polygon with 1175 diagonals has 50 sides
no
square and rectangle
A cone does not have any diagonals in the traditional sense, as diagonals are defined in polygons. A cone has a circular base and a single vertex at the top, making it a three-dimensional shape rather than a polygon. Therefore, it does not possess diagonals like a polygon does.
In general, the diagonals of irregular polygons do not bisect the angles at their vertices. Specifically, in shapes such as trapezoids, kites, and irregular quadrilaterals, the diagonals may intersect at angles that do not evenly split the angles of the vertices. This contrasts with regular polygons, where diagonals do bisect angles due to their symmetrical properties.
50*(50 - 3)/2 = 1175 diagonals.
It works out that a polygon with 1175 diagonals has 50 sides
no
Regular polygons. A square and rectangle will have congruent (equal length) diagonals.
It has 464 diagonals. I used n(n-3)/2. Works for all polygons.
The principal diagonals of all regular polygons.
It is not possible to answer the question since there are no polygons "following".
All regular polygons.
square and rectangle
rectangle
A square, a rhombus and a kite all have perpendicular diagonals that intersect at right angles
A cone does not have any diagonals in the traditional sense, as diagonals are defined in polygons. A cone has a circular base and a single vertex at the top, making it a three-dimensional shape rather than a polygon. Therefore, it does not possess diagonals like a polygon does.