It has 464 diagonals. I used n(n-3)/2. Works for all polygons.
38 diagonals
In a polygon with n sides, the number of diagonals that can be drawn from one vertex is given by the formula (n-3). Therefore, in a 35-sided polygon, you can draw (35-3) = 32 diagonals from one vertex.
It has 32 lines of symmetry.
A polygon with 32 sides is known as a triacontakaidigon.
32. 16 through opposite vertices and 16 through the centres of opposite sides.
38 diagonals
(35*(35-3))/2 (35*32)/2 1120/2 560 diagonals
In a polygon with n sides, the number of diagonals that can be drawn from one vertex is given by the formula (n-3). Therefore, in a 35-sided polygon, you can draw (35-3) = 32 diagonals from one vertex.
A regular polygon with 32 sides has 32 lines of symmetry. Each line of symmetry passes through a vertex and the midpoint of the opposite side or through the midpoints of two opposite sides. This symmetry results from the equal length and angles of all sides and vertices in the polygon.
It has 32 lines of symmetry.
A polygon with 32 sides is known as a triacontakaidigon.
It will have: (5400+360)/180 = 32 sides
Infinitely many. Consider a regular polygon with n sides where n > 2. Let x = 32/n. Then the perimeter of the polygon is n*(32/n) = 32.
32. 16 through opposite vertices and 16 through the centres of opposite sides.
Because all the vertices are already joined together. The formula for the diagonals of a polygon is: 1/2*(n2-3n) where n is the number of sides A triangle has 3 sides and 1/2*(32-9) = 0
gghg a regular polygon has a 32 sides. calculate the size of each interior angle.
The sum of interior angles of a polygon with 'n' sides = 180( n - 2 ) degrees Replace n with 32 We get 5400 degrees.