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The number of diagonals that can be drawn in a polygon with n sides can be determined by nn - 32 How many diagonals can be drawn in a polygon with 10 sides?
38 diagonals
How many diagonals can you drawn from one vertex in a 35 sided polygon?
In a polygon with n sides, the number of diagonals that can be drawn from one vertex is given by the formula (n-3). Therefore, in a 35-sided polygon, you can draw (35-3) = 32 diagonals from one vertex.
How many lines of symmetry does a regular polygon has with 32 sides?
It has 32 lines of symmetry.
What is a 32-sided polygon called?
A polygon with 32 sides is known as a triacontakaidigon.
How many lines of symmetry does a regular polygon with 32 sides have?
32. 16 through opposite vertices and 16 through the centres of opposite sides.
The number of diagonals that can be drawn in a polygon with n sides can be determined by nn - 32 How many diagonals can be drawn in a polygon with 10 sides?
38 diagonals
If a polygon has 35 diagonals then how many sides does it have?
(35*(35-3))/2 (35*32)/2 1120/2 560 diagonals
How many diagonals can you drawn from one vertex in a 35 sided polygon?
In a polygon with n sides, the number of diagonals that can be drawn from one vertex is given by the formula (n-3). Therefore, in a 35-sided polygon, you can draw (35-3) = 32 diagonals from one vertex.
How many lines of symmetry does a regular polygon has with 32 sides?
It has 32 lines of symmetry.
What is a 32-sided polygon called?
A polygon with 32 sides is known as a triacontakaidigon.
How many sides does a polygon with intiror angles of 5400 degrees?
It will have: (5400+360)/180 = 32 sides
How many ways add up to the perimeter of 32?
Infinitely many. Consider a regular polygon with n sides where n > 2. Let x = 32/n. Then the perimeter of the polygon is n*(32/n) = 32.
How many lines of symmetry does a regular polygon with 32 sides have?
32. 16 through opposite vertices and 16 through the centres of opposite sides.
Why is it not possible to draw a diagonal of a triangle?
Because all the vertices are already joined together. The formula for the diagonals of a polygon is: 1/2*(n2-3n) where n is the number of sides A triangle has 3 sides and 1/2*(32-9) = 0
Number of triangles in a 32 side polygon?
gghg a regular polygon has a 32 sides. calculate the size of each interior angle.
What is the sum of the interior angle of a polygon with 32 sides?
The sum of interior angles of a polygon with 'n' sides = 180( n - 2 ) degrees Replace n with 32 We get 5400 degrees.
What is the size of each individual interior angle of a polygon having 464 diagonals showing key stages of work?
Providing that it is a regular polygon then let its sides be x: So: 0.5*(x2-3x) = 464 diagonals Then: x2-3x-928 = 0 Solving the equation: x = 32 sides Total sum of interior angles: 30*180 = 5400 degrees Each interior angle: (5400+360)/180 = 168.75 degrees
