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If using numbers 1 thru 49 how many 6 digit combinations can be made?
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
How many numbers are in Uno?
1 thru 9
What is the product of the 10 single digit numbers?
362,880 edit: 3,628,800 edit: Sorry, Whizkid. You included '10', whereas the question clearly stated "single-digit numbers". Now that we think about it, the "10 single digit numbers" must include zero, so the product is zero. But for the digits 1 thru 9, the product is still 362,880 .
How many 3 digit numbers have at least one repeated digit?
There are a total of 900 3-digt numbers (100 thru 999); Of these there are 9x9x8 = 648 numbers that do not contain repeating digits (first position: 9 possibilities, second place 9 possibilities; the 10 digits minus the one used in the first place. and third place 8 possibilities; 10 digits minus the two used in the first and second places) So, there should be 900-648=252 3-digit numbers with at least one repeating digit.
How many whole numbers have exactly 4 digits?
9000 of them. All of the numbers 1 thru 9999 EXCEPT 1 thru 999. 9999 - 999 = 9000.
