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How many possible orders are there with these numbers - 3 5 7 and 9?
Wiki User
∙ 10y ago
As there are 4 numbers and they are all different, they can be arranged in:
4 choices for first number, leaving
3 choices for the second number for each choice of the first, leaving
2 choices for the third number for each of the choices of the first two, leaving
1 choice for the last number for each of the choices for the first three
giving:
number of choices = 4 x 3 x 2 x 1 = 24 possible orders in total.
Wiki User
∙ 10y ago
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-2
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450
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-2
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1004
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If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
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What are 3 numbers that can multiply to 150?
450
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