9!/6!, if the six different orders of any 3 digits are considered distinct combinations.
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Exactly 3,628,800, or 10!.
10!/3! = 604800 different combinations.
Through the magic of perms and coms the answer is 729
If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.
There are 360 of them.