For each football match, there are typically three possible outcomes: a win for the home team, a win for the away team, or a draw. Therefore, for 5 football matches, the total number of possible outcomes is calculated as (3^5). This results in 243 possible outcomes for the 5 matches.
There are 25 = 32 possible outcomes.
There are 36 possible outcomes: 6 for each die.
2x2x2=8 possible outcomes. In general for n tosses there are 2^n outcomes.
If the numbers and letters can be repeated then there are 45,697,600 possible outcomes. If the letters and numbers can not be repeated there are 32,292,000 possible outcomes.
The are 52 possible outcomes if you pick a card from a deck of 52.
Since there are two teams, and ten games, there are 20 possible outcomes, since either team may win each game.
IF YOU HAVE ONE GAME, YOU HAVE A POSIBILITY OF 3 OUTCOMES, IF YOU HAVE 2 GAMES IT GO'S UP TO 9 POSIBILE OUTCOMES. FIRST ANSWER 1X3=3 SECOND IS 3X3=9 FOR 10 GAMES IT IS 3X3 TEN TIMES 3X3X3X3X3X3X3X3X3X3=59,049 POSSIBLE COMBINATIONS (I THINK)HA HA
There are 36 possible outcomes.
There are 25 = 32 possible outcomes.
There are 23 = 8 possible outcomes.
3 + 3 + 3 + 3 + 3 = 15 total possible outcomes. You can 'prove' this by laying out a table of possibles where a user might tick the result of each game..... Match....1....2....3....4....5 Win......._...._...._...._...._ Lose......_...._...._...._...._ Draw....._...._...._...._...._
There are 26 = 64 possible outcomes.
There are 26 = 64 possible outcomes.
South Africa have won probably 50 or less football matches.
I believe there would be 11 possible outcomes!
There are 36 possible outcomes: 6 for each die.
If the numbers (or symbols) are all different then 10 outcomes.