If my math is correct it would take an additional ( .6 of a U.S. quart of
antifreeze ) to increase a 30 % antifreeze volume to 40 % if the total
volume of the mixture is 6 quarts
4.2 quarts
(X gal)(0.15) = (1 gal)(0.025)0.15X = 0.025X = 0.17 gallons (4 quarts/1 gal.)(1 liter/1.06 quarts)(1000 ml/1 liter)= 642 milliliters============
If 'X' is the number of quarts of 6 percent butterfat milk and 'Y' is the number of quarts of the 1 percent butterfat milk then: x + y = 75 quarts and (6x + 1y)/75 = 4 (because we want 4 percent per quart) then solving for the system of equations leads to: x = 45 quarts (the 6 percent) and y = 30 quarts (the 1 percent)
20% of 12 quarts= 20% * 12= 0.2 * 12= 2.4 quarts or 76.8 ounces (US measure)
To find out how many quarts of water must be added, we first calculate the amount of pure substance in the 80 percent mixture. In 4 quarts of an 80 percent mixture, there are 3.2 quarts of the substance (0.8 x 4). Let ( x ) be the amount of water added. The total volume after adding water will be ( 4 + x ) quarts, and we want this to equal a 50 percent concentration, which gives the equation ( 3.2 = 0.5(4 + x) ). Solving for ( x ) gives ( 3.2 = 2 + 0.5x ), resulting in ( 0.5x = 1.2 ), or ( x = 2.4 ). Therefore, 2.4 quarts of water must be added.
The original solution has 3.6 quarts of antifreeze in it. The equation then becomes (3.6 + x)/(12 + x) = 0.40, where x is the amount of antifreeze added. X is then equal to 2.
4.2 quarts
You need 1 1/3 quarts of pure antifreeze.
In the original solution, you have 5 quarts total, 20% antifreeze. So 20% * 5 = 1. You have 4 qt water and 1 qt antifreeze. You will add an amount A, to this mixture. When you add, the new total volume (in quarts) is 5 + A, and the percentage is:(1 + A)/(5 + A) x 100%. So when you start out at A = zero, you have 1/5 x 100% = 20%.So set up the equation (1 + A)/(5 + A) * 100 = 30, and solve for A.Multiply both sides by (5+A) and isolate the term A. Note that since you are adding, the value of A will never be negative (so you don't have to worry about the denominator (5+A) being zero.Answer = 5/7 (quarts) = 0.714285714285155 quarts.
I'd go buy a bottle of pre-mixed antifreeze, and just fill it up with that. Less hassle, works great.
4 quarts or one gallon of pure antifreeze, mixed with an equal amount of distilled water, for a 50/50 mix.
30 quarts of 2 percent 15 quarts of 5 percent
9.1 US quarts
For the 2003 Ford Ranger with a 3.0 liter V6 engine and AUTOMATIC transmission ( 7.4 quarts of antifreeze ) * That's for a 50 / 50 mix of 7.4 quarts of antifreeze and 7.4 quarts of preferably distilled water * because the engine cooling system capacity is 14.8 quarts according to the owners manual
For a 1987 Mercury Grand Marquis : For the 5.0 liter / 302 cubic inch V8 engine ( 7.5 quarts of antifreeze with 7.5 quarts of preferably distilled water should give you a 50 / 50 mix of engine coolant ) --------------------------------------------------------------------------- For the 5.8 liter / 351 cubic inch ( 8.0 quarts of antifreeze )
(X gal)(0.15) = (1 gal)(0.025)0.15X = 0.025X = 0.17 gallons (4 quarts/1 gal.)(1 liter/1.06 quarts)(1000 ml/1 liter)= 642 milliliters============
2 gallons of non-toxic antifreeze