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When the discriminant is greater than 0 how many real roots are there?
There will be 2 real roots
How many real roots exist if the discriminant of the eqation0?
If the discriminant of a quadratic equation is 0 then it has two equal real roots.
What are the differences between a and a square roots?
a is a real number since we use just letters to represent real numbers. if a > 0, then its square root is also a real number, so it has two square roots, one positive and one negative. Be careful when you use the radical sign, because it is looking only for the principal square root of a, which is the positive one. if a < 0, then its square root is an imaginary number.
-6 square roots of 3 plus 6 square roots of three?
It is: 0
How does discriminant enable us to identify the number and type of solutions roots of a quadratic function?
If the quadratic equation is ax2 + bx + c = 0 then if the discriminant, b2 - 4ac is greater than 0: there are two real roots = [-b + or - sqrt(b2 - 4ac)]/2a equal to 0: there are two real coincidental roots, with the value -b/2a less than 0: there are two complex roots = [-b + or - i*sqrt(b2 - 4ac)]/2a where i is the imaginary square root of -1. The answer to the third case (discr<0) may be given as "there are no real roots".
