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When the discriminant is greater than 0 how many real roots are there?
There will be 2 real roots
How many real roots exist if the discriminant of the eqation0?
If the discriminant of a quadratic equation is 0 then it has two equal real roots.
What are the differences between a and a square roots?
a is a real number since we use just letters to represent real numbers. if a > 0, then its square root is also a real number, so it has two square roots, one positive and one negative. Be careful when you use the radical sign, because it is looking only for the principal square root of a, which is the positive one. if a < 0, then its square root is an imaginary number.
-6 square roots of 3 plus 6 square roots of three?
It is: 0
How does discriminant enable us to identify the number and type of solutions roots of a quadratic function?
If the quadratic equation is ax2 + bx + c = 0 then if the discriminant, b2 - 4ac is greater than 0: there are two real roots = [-b + or - sqrt(b2 - 4ac)]/2a equal to 0: there are two real coincidental roots, with the value -b/2a less than 0: there are two complex roots = [-b + or - i*sqrt(b2 - 4ac)]/2a where i is the imaginary square root of -1. The answer to the third case (discr<0) may be given as "there are no real roots".
When the discriminant is greater than 0 how many real roots are there?
There will be 2 real roots
How many square roots does 0 have?
The square root of 0 is 0. Since 0 has no positive or negative equivalent, this is its only square root.
How many square roots does every number have?
All positive numbers have two. 0 has only one. Negative numbers have two imaginary roots but no real ones.
How many real roots exist if the discriminant of the eqation0?
If the discriminant of a quadratic equation is 0 then it has two equal real roots.
What are the differences between a and a square roots?
a is a real number since we use just letters to represent real numbers. if a > 0, then its square root is also a real number, so it has two square roots, one positive and one negative. Be careful when you use the radical sign, because it is looking only for the principal square root of a, which is the positive one. if a < 0, then its square root is an imaginary number.
How many real roots can a fourth degree polynomial have?
Upto 4. If the coefficients are all real, then it can have only 0, 2 or 4 real roots.
Are square roots real numbers?
Yes, if the number whose square root we are taking is greater than 0. Only if you try to take the square root of a negative number will you get back an imaginary number. Square roots are often irrational, but that's different from real versus imaginary.
-6 square roots of 3 plus 6 square roots of three?
It is: 0
How do you found two squares roots for 1?
The two square roots are -1 and +1.For any real number, x, other than 0, if y is the square root of x then so is -y.
How does discriminant enable us to identify the number and type of solutions roots of a quadratic function?
If the quadratic equation is ax2 + bx + c = 0 then if the discriminant, b2 - 4ac is greater than 0: there are two real roots = [-b + or - sqrt(b2 - 4ac)]/2a equal to 0: there are two real coincidental roots, with the value -b/2a less than 0: there are two complex roots = [-b + or - i*sqrt(b2 - 4ac)]/2a where i is the imaginary square root of -1. The answer to the third case (discr<0) may be given as "there are no real roots".
How many real roots exist if the discriminant of the equation plus 0?
If the discriminant of a quadratic equal is zero then it will have two equal roots.
Is the square root of 0 a real number?
The square root of 0 is 0, which is a real number.
