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The answer would be a general solution to length x height = length+length+height+height.

I can only think of one - a square with sides of 4. The area would be 4x4=16 and the perimeter would be 4+4+4+4=16. If the rectangle is longer in either direction, the perimeter would be bigger than its area (e.g. a 1x4 rectangle (area=4) would have a perimeter 1+1+4+4=10, as would squares smaller than 4x4 (e.g. 3x3=9, perimeter=3+3+3+3=12). Squares bigger than 4x4 would have a larger area (e.g. 5x5=25, 5+5+5+5=20)

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Q: How many rectangles have the same are as its perimeter?
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