To find the roots of the polynomial (3x^5 + 2x^3 + 3x), we can factor out the common term, which is (x):
[ x(3x^4 + 2x^2 + 3) = 0. ]
This shows that (x = 0) is one root. The quartic polynomial (3x^4 + 2x^2 + 3) does not have real roots (as its discriminant is negative), meaning it contributes no additional real roots. Therefore, the polynomial has only one real root, which is (x = 0).
since 15 = 3x5, 6 = 2x3, 9 = 3x3 answer = 2x3x3x5 = 90
60
true 2x3=6 LCM (2,3)=6 3x5=15 LCM (3,5)=15 2x5=10 LCM (2,5)=10
No, a 3x5 matrix cannot be multiplied by another 3x5 matrix. For matrix multiplication to be possible, the number of columns in the first matrix must equal the number of rows in the second matrix. Since a 3x5 matrix has 5 columns and the second 3x5 matrix has 3 rows, multiplication is not defined in this case.
1080 = 2^3x3^3x5 200= 2^3x5^2 LCM (1080,200) = 2^3x3^3x5^2 = 1800
(2x3)+(3x5)-(3x2)= 2x3=6 3x5=15 3x2=6 So..... 6x25-6= 6x25=150 150+6=156
6 is 2x3 and 15 is 3x5 just basic facts no exponents
prime factorization of each: 2x3 , 3x5, 2x2x5 so LCM = 2x2x3x5 = 60
There are 15 cells in a 3x5 table, calculated by multiplying the number of rows (3) by the number of columns (5).
since 15 = 3x5, 6 = 2x3, 9 = 3x3 answer = 2x3x3x5 = 90
60
true 2x3=6 LCM (2,3)=6 3x5=15 LCM (3,5)=15 2x5=10 LCM (2,5)=10
1080 = 2^3x3^3x5 200= 2^3x5^2 LCM (1080,200) = 2^3x3^3x5^2 = 1800
4 = 4, and 4 = 2 x 2, so either a single prime number to the power 4-1 (23, 33, etc.), or two different prime numbers, each to the power 2-1, for example, 2x3, 2x5, 3x5, etc.
Divide the area of the windows by the area of the sheets. Note: 3x5 and 2x4 are not areas, they are numbers. And you don't say how big the sheets are, so it is difficult to be helpful.
1x15 3x5
15