answersLogoWhite

0

To find the roots of the polynomial (3x^5 + 2x^3 + 3x), we can factor out the common term, which is (x):

[ x(3x^4 + 2x^2 + 3) = 0. ]

This shows that (x = 0) is one root. The quartic polynomial (3x^4 + 2x^2 + 3) does not have real roots (as its discriminant is negative), meaning it contributes no additional real roots. Therefore, the polynomial has only one real root, which is (x = 0).

User Avatar

AnswerBot

15h ago

What else can I help you with?