There is a potentially large number of shapes with a perimeter of 16 and an area of 15. You would just have to do some experimenting and find out. However, the easiest one that came to my mind when I saw this question was a rectangle, with shorts sides of 3 and long sides of 5. Add the four sides together (3+5+3+5), and you get the perimeter of 16. Multiply the two numbers together (3x5), and you get the area of 15. A standard index card, for instance, measures 3 inches by 5 inches, so that would have a perimeter of 16 inches and an area of 15 square inches.
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
The perimeter is not going to have sq units. If the perimeter of a square is 15 units then the area would be 14.0625units squared.
In general the larger the perimeter (of a flat shape) the greater the area. Given two congruent shapes the one with the larger perimeter has a greater area.But two shapes that are not congruent (or almost so) do not follow this rule: for example a rectangle fifteen units long and one unit wide has an area of 15 square units and a perimeter of 32 units. While a square with edges four units has an area of sixteen square units (one more than the other rectangle) but a perimeter of only sixteen units (half that of the long thin rectangle).So too with surface area and volume. Of two congruent 3 dimensional shapes, the one with the larger volume will also have a larger surface area.
If the perimeter is 15, he apothem cannot be 18.1
There is no such shape. Firstly, because no shape can jave an area of 100 cm. Suppose, though, that its area were 100 SQUARE cms, even then, there is no possible solution. Of all the shapes possible with a given perimeter, a circle has the greatest area. A perimeter of 30 cm means a radius of 30/(2*pi) = 15/pi cm. A circle with this radius would have an area of pi*(15/pi)2 = 225/pi = 71.62 sq cm : well below the area required.
Oh, what a happy little question! Let's think about shapes that could have a perimeter of 15 and an area of 16. One shape that comes to mind is a rectangle with dimensions 4 by 4. Another possibility is a square with sides of length 4. These shapes show us that there can be different ways to create beautiful combinations of perimeter and area.
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
The perimeter is not going to have sq units. If the perimeter of a square is 15 units then the area would be 14.0625units squared.
In general the larger the perimeter (of a flat shape) the greater the area. Given two congruent shapes the one with the larger perimeter has a greater area.But two shapes that are not congruent (or almost so) do not follow this rule: for example a rectangle fifteen units long and one unit wide has an area of 15 square units and a perimeter of 32 units. While a square with edges four units has an area of sixteen square units (one more than the other rectangle) but a perimeter of only sixteen units (half that of the long thin rectangle).So too with surface area and volume. Of two congruent 3 dimensional shapes, the one with the larger volume will also have a larger surface area.
If the perimeter is 15, he apothem cannot be 18.1
If it's a rectangle then:- Area = 15*12 = 180 square units Perimeter = 15+15+12+12 = 54 units of measurement
There is no such shape. Firstly, because no shape can jave an area of 100 cm. Suppose, though, that its area were 100 SQUARE cms, even then, there is no possible solution. Of all the shapes possible with a given perimeter, a circle has the greatest area. A perimeter of 30 cm means a radius of 30/(2*pi) = 15/pi cm. A circle with this radius would have an area of pi*(15/pi)2 = 225/pi = 71.62 sq cm : well below the area required.
Perimeter: 150+15+150+15 = 330 feet Area: 150*15 = 2250 square feet
The area cannot be 15 feet since that is a measure of length, not area. In any case, information about the area cannot determine the perimeter; it can only put a lower limit on it. The perimeter can be anyhting from 15.49193 ft upwards. Consider the following rectangles, all with area = 15 square feet: a sqrt(15)*sqrt(15) rectangle will have a perimeter of 4*sqrt(15) = 15.49193 ft (approx). 1ft*15ft rectangle will have a perimeter of 32 feet 0.1ft*150ft rectangle: perimeter = 300.2 feet 0.01ft*1500ft rectangle: perimeter = 3000.02 ft 0.001ft*15000ft rectangle: perimeter = 30000.002 ft by now you should see that there is no upper limit to the perimeter.
Without going into detail at the moment, I'd have to say Yes it's possible. See the related question for thought process.
It depends on the shape of the area. It the shape is a square, the perimeter would be 1,022 feet.
Perimeter = 15+15+15+15 = 60 feet Area = 15*15 = 225 square feet