Oh, what a happy little question! Let's think about shapes that could have a perimeter of 15 and an area of 16. One shape that comes to mind is a rectangle with dimensions 4 by 4. Another possibility is a square with sides of length 4. These shapes show us that there can be different ways to create beautiful combinations of perimeter and area.
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To find shapes with a perimeter of 15 and an area of 16, we can use the formulas for perimeter and area of different shapes. One possible solution is a rectangle with dimensions 4x4, as the perimeter would be 2(4+4)=16 and the area would be 4x4=16. Another solution is a square with side length 4, as the perimeter would be 4x4=16 and the area would be 4^2=16. These are the two shapes that meet the criteria of a perimeter of 15 and an area of 16.
Well, honey, you're looking for a rectangle with sides of 4 and 4.5 units. Don't go thinking outside the box on this one - stick to the good ol' rectangles for this one.
4x4 square: perimeter - 16 area - 16 6x2 rectangle perimeter - 16 area - 12
The perimeter is 16 feet.
* It is unclear if the question is asking about two rectangles, each with a perimeter of 16, or two rectangles whose perimeters sum to 16. This answer assumes the former.Other than the 4x4 square, which coincidentally has both a perimeter and area of 16, some examples would be:1 x 7 rectangle : perimeter 16 in. , area 7 sq. in2 x 6 rectangle : perimeter 16 in., area 12 sq. in3 x 5 rectangle: perimeter 16 in., area 15 sq. inYou can calculate that for a given perimeter, the largest area is found in the square with a side measurement of P/4, i.e. the length and the width are the same.
Area = (side)2 = 16 square centimeters Perimeter = 4 x side = 16 centimeters
A rectangle has 2 pairs of equal sides. perimeter is the sum of the lengths of all sides: Perimeter = 12 + 12 + 16 + 16 = 56 Ft Area = 12 x 16 = 192 Ft2