To determine the number of sides ( n ) in a polygon with 252 diagonals, we use the formula for the number of diagonals in a polygon: ( D = \frac{n(n-3)}{2} ). Setting this equal to 252 gives us the equation ( \frac{n(n-3)}{2} = 252 ). Solving this leads to ( n(n-3) = 504 ), or ( n^2 - 3n - 504 = 0 ). The positive solution to this quadratic equation is ( n = 24 ), so the polygon has 24 sides.
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1/2*(252-75) = 275 diagonals
(n x n - 3n)/2 (24 x 24 - 3x24)/2 (576 - 72)/2 504/2 = 252
An exterior angle of 2520 degrees is impossible. Assuming you mean 252 degrees, this would make each interior angle 108 degrees, as 360- 252 = 108. A regular polygon with 108-degree interior angles has 5 sides, or in other words, it is a regular pentagon.
252 / 1,000 = 63 / 250 by dividing both sides by 4
There are 36 weeks in 252 days.