Let its sides be x and rearrange the diagonal formula into a quadratic equation:-
So: 0.5(x^2-3x) = 252
Then: x^2-3n-504 = 0
Solving the quadratic equation: gives x a positive value of 24
Therefore the polygon has 24 sides irrespective of it being irregular or regular
A 7 sided polygon has 14 diagonals
It will have 13 sides because 0.5*(132-39) = 65 diagonals
11
The equation is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
64 sides = 64 angles From one angle you can draw (64 - 2) diagonals = 62. Lines from an angle to the immediately adjacent angles are sides, not diagonals.
It has 9 sides and it can be an regular or a irregular polygon which is called a nonagon Check: 0.5*(81-27) = 27 diagonals
Let the number of sides be x and by solving the equation for diagonals 0.5(x*x-3x) = 135 the solution is -15 or 18 and so therefore it has 18 sides irrespective if it is an irregular or a regular polygon
Let its sides be x and use the formula: 0.5*(x squared-3x) = 230 So: x squared-3x-460 = 0 Solving the quadratic equation gives x positive value of 23 Therefore the polygon has 23 sides irrespective of it being a regular or an irregular polygon. Check: 0.5*(23^2-(3*23)) = 230 diagonals
how many diagonals are there iin a polygon of 11 sides
A polygon that has 104 diagonals will have 16 sides
A regular octogon (8 sides) has 20 diagonals. An irregular octogon also has 20 diagonals, but only if all its points point outwards.
That polygon is called a "triangle". It has no diagonals.
A 7 sided polygon has 14 diagonals
Suppose the polygon has V vertices.Then sum of interior angles is (V - 2)*180 degrees = 1980 degrees => V - 2 = 1980/180 = 11 => V = 13 A polygon with V vertices has V*(V-3)/2 = 13*10/2 = 65 diagonals.
38 diagonals
There are 77 diagonals
An heptagon has 7 sides and 14 diagonals