It wouldn't exist if the angles added up to 172o: the minimum sum for the angles of a polygon is that of a triangle, 180o - all the polygons with more sides are multiples of this, namely 4 sides => sum is 360o, 5 sides => sum is 540o, etc.
If you mean:
How many sides would a polygon have if all the angles were 172 degrees?
then the answer is 45 sides.
For all polygons:
For a regular polygon:
Interior angle = 1720 => exterior_angle = 8o
=> number_of_sides = 360o / 8o = 45.
E
A regular polygon with exterior angles of 30 degrees has: 360/30 = 12 sides
If all of its exterior angles are 90 degrees then it will have 4 sides
It is a quadrilateral polygon that has 4 sides and 4 interior angles that add up to 360 degrees.
Exterior angles = 360 degrees Interior angles = 2340 degrees
360 degrees
Any polygon can have two interior angles of 12 degrees. No polygon can have all its interior angles of 12 degrees.
If each interior angles is 179 degrees, then the polygon has 360 sides
2800 degrees * * * * * No. The interior angles of a polygon with n sides is (n-2)*180 degrees. Here, n = 12 so the answer is 1800 degrees. A polygon whose interior angles added to 2800 degrees would have 17 5/9 sides! Since a fractional number of sides is impossible, so is such a polygon.
A regular polygon with exterior angles of 30 degrees has: 360/30 = 12 sides
15 sides
35 sides
That's true if the interior angles are 108 degrees, but a regular polygon cannot have exterior angles of 108 degrees.
By 900 degrees as for example a triangle has 3 sides that add up to 180 degrees then if 5 sides are added to it then it then is an 8 sided octagon with interior angles that add up to 1080 degrees
If all of its exterior angles are 90 degrees then it will have 4 sides
If all of the interior angles of the polygon add up to 180 degrees, then the polygon is a triangle.
The polygon would be a heptagon.So, the polygon would have 7 sides.
A polygon whose interior angles are 2880 degrees has 18 sides.