74.6, to 3 significant digits.
No. Pi is a transcendental number which is a kind of irrational number. It has an infinite decimal representation which does not end nor does it go into a recurring cycle. That does not mean that there are no repeated digits, it simply means that digits may repeat themselves for a little while but then continue in what appears to be a random pattern. Not only does it not have an infinite decimal representation, but infinite binary, ternary, etc representations.
It's a number system. For example, base 10 means that you have ten digits, 0 1 2 3 4 5 6 7 8 9, before you go to double digits (10). With base 2, you have only two digits, 0 1, before you go to double digits (10).
"How many times does 95 go into 931?" is the same as asking "How much is 931 divided by 95?" Thus, the answer can be calculated as follows: 931/95 = 9.8
Answer: No. Pi is irrational; we could never find the last digit, because the digits go on forever. Also, being irrational means that the digits don't repeat periodically.
74.6, to 3 significant digits.
Because Pi is known to be an irrational number it means that the digits never end or repeat in any known way. But calculating the digits of Pi has proven to be an fascination for mathematicians throughout history. Some spent their lives calculating the digits of Pi, but until computers, less than 1,000 digits had been calculated. In 1949, a computer calculated 2,000 digits and the race was on. Millions of digits have been calculated, with the record held (as of September 1999) by a supercomputer at the University of Tokyo that calculated 206,158,430,000 digits. (first 1,000 digits). However, learning 3.141, is all that is necessary. But you can go on and on, to infinity, and never find the exact circumference of a circle. I have only memorized 205 digits of pi; and yes I do use it to find the circumference of a circle.
their both based on units of measure
To round 0.00076321 cg to three significant figures, identify the first three non-zero digits starting from the left. In this case, the first three significant digits are 7, 6, and 3. Since the next digit (2) is less than 5, the 3 remains unchanged. Therefore, the rounded number is 0.000763 cg.
It will go up to 999,999It will go up to 999,999
There are 4 significant numbers in 9400 . If in a number decimal is absent , then all digits in that number are significant . Ans #2 Since the example you give is not a measurement, it must be a count or an absolutely precise number. As such, all digits are significant...and all digits out to infinity are significant. 9400 dogs is an absolute count because you can't have a fraction of a dog. It is, however, irrelevant to discuss precision of an absolute count because it is infinitely precise. 2 measurements of 1.5 inches means multiply 2 (absolutely precise) × 1.5 inches (precise to the tenth of an inch) = 3.0 inch (precise to the tenth of an inch). Two baskets with four kittens each is exactly eight kittens. Since it is an absolute count, it is absolutely precise. If you need to represent the precision of an estimated count, you can say 9400 ±100 dogs This means that you have 2 significant digits: 9400 give or take a hundred. Any math you do with that estimated count will need to carry that imprecision along with it. The estimated part of a measurement is likewise significant. If the number is a measurement, ex. 9400 inches, the zeros are not significant because they are only placeholders. For them to be considered significant they would need to be barred (write a small bar above them such as you do for a repeating decimal). For measurements, the rules go: * All non-zero digits are significant; * Zeros between significant digits are significant; * Zeros that serve only as placeholders are not significant unless marked. If the measurement had been 9400.0 inches, the zero trailing the decimal point is significant because it is not serving as a placeholder. It is a meaningful part of the precision of the measurement. It says that you estimated the measurement to the tenth of an inch. If the measurement were 0.0094 inches, the zero to the left of the decimal point is not significant. It is placed there so you don't confuse the decimal point as a period belonging to the sentence that came before. The next 2 zeros are only serving as placeholders and they, even if marked, do not improve the precision. It would be meaningless to mark them as significant. This measurement has only 2 significant digits.
This is easy. Just sort the digits in descending order. That works because the further left you go, the more significant the digit. So the largest number that can be made out of the digits 5, 3, 1, 4, and 7 is 75,431.
8. A way to work this out is figure out how many possible digits can go in each place value position (units, tens, hundreds) and multiply these together. Since there are 2 possible digits that can go in each position and there are three positions, you would go: 2 x 2 x 2 = 8 Want a list? 222 225 252 255 555 552 525 522
Over/about 13 million digits! wow that's a long number! if you wanna see it, go to www.math.Utah.edu/~pa/math/largeprime.HTML
No. Pi is a transcendental number which is a kind of irrational number. It has an infinite decimal representation which does not end nor does it go into a recurring cycle. That does not mean that there are no repeated digits, it simply means that digits may repeat themselves for a little while but then continue in what appears to be a random pattern. Not only does it not have an infinite decimal representation, but infinite binary, ternary, etc representations.
As many as humans have (up til the current moment) endeavored to name and describe... But logically, infinite of course. They go on forever
Seven: 10, 16, 20, 25, 40, 50, 80.