In which country?
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36n where n is the number of digits allowed in the plate. If a blank space is acceptable as a digit, then that becomes 37n.
If I understand correctly the first number has to be '1', the next three digits have to be letters, and the last digit can't be '0', so there are1x26x26x26x10x10x9 = 15,818,400 possible Californian licence plate combinations.
10,108,800 assuming that leading 0s are not allowed in the 3-digit numbers; that the licence authorities do not block some letter combinations because they are rude, and letters that might be confused with numbers (O and 0, I and 1, Z and 2, S and 5, B and 8) are all permitted.
11,232,000
(26) x (26) x (10,000) = 6,760,000