None but it can be simplified to: 162x-468
To find the number of solutions for the equation ( 6x + 15 = 6(x - 3) ), we first simplify both sides. Expanding the right side gives ( 6x + 15 = 6x - 18 ). Subtracting ( 6x ) from both sides results in ( 15 = -18 ), which is a false statement. Therefore, there are no solutions to this equation.
2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
To solve the equation ( 6x + 30 + 4x = 10(x + 3) ), first simplify both sides. Combine like terms on the left to get ( 10x + 30 = 10x + 30 ). This shows that both sides are equal for all values of ( x ), indicating that there are infinitely many solutions to the equation.
2sin2(6x) + 3sin(6x) + 1 = 0 Solving the quadratic, sin(6x) = -1 or sin (6x) = -0.5 sin(6x) = -1 => 6x = 45+60n degrees for integer n sin(6x) = -0.5 => 6x = 35+60n or 55+60n degrees for integer n.
The expression (6x^{16} - 22 + 6x) is a polynomial in (x) of degree 16. A polynomial of degree (n) can have up to (n) real solutions. Therefore, this polynomial can have up to 16 solutions, depending on the specific values of the coefficients and the nature of the roots.
To find the number of solutions for the equation ( 6x + 15 = 6(x - 3) ), we first simplify both sides. Expanding the right side gives ( 6x + 15 = 6x - 18 ). Subtracting ( 6x ) from both sides results in ( 15 = -18 ), which is a false statement. Therefore, there are no solutions to this equation.
x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)
2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
To solve the equation ( 6x + 30 + 4x = 10(x + 3) ), first simplify both sides. Combine like terms on the left to get ( 10x + 30 = 10x + 30 ). This shows that both sides are equal for all values of ( x ), indicating that there are infinitely many solutions to the equation.
2sin2(6x) + 3sin(6x) + 1 = 0 Solving the quadratic, sin(6x) = -1 or sin (6x) = -0.5 sin(6x) = -1 => 6x = 45+60n degrees for integer n sin(6x) = -0.5 => 6x = 35+60n or 55+60n degrees for integer n.
The expression (6x^{16} - 22 + 6x) is a polynomial in (x) of degree 16. A polynomial of degree (n) can have up to (n) real solutions. Therefore, this polynomial can have up to 16 solutions, depending on the specific values of the coefficients and the nature of the roots.
Given 6x + (7x-8) = -5 6x + 7x - 8 = -5 ==> 13x = 3 therefore, x = 3/13
It needs to have an equality or equality signs to have solutions for it.Without any equality signs the given expression can't be considered to be an equation although it might be possible to simplify it.
x2 + 6x = 16=> x2 + 6x - 16 = 0=> x2 + 8x -2x - 16 = 0=> (x+8)(x-2) = 0=> x = -8 or x = 2So, the solutions of the quadratic equation x2 + 6x = 16 are -8 and 2.
The quadratic equation will have two solutions.
There are no solutions to this quadratic equation because the discriminant is less than zero.
9x2+6x-7 = 0 Using the quadratic equation formula:- x = 0.6094757082 or x = -1.276142375