The expression (6x^{16} - 22 + 6x) is a polynomial in (x) of degree 16. A polynomial of degree (n) can have up to (n) real solutions. Therefore, this polynomial can have up to 16 solutions, depending on the specific values of the coefficients and the nature of the roots.
2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
To find the number of solutions for the equation ( 6x + 15 = 6(x - 3) ), we first simplify both sides. Expanding the right side gives ( 6x + 15 = 6x - 18 ). Subtracting ( 6x ) from both sides results in ( 15 = -18 ), which is a false statement. Therefore, there are no solutions to this equation.
x2 + 6x = 7 ⇒ x2 + 6x + 9 = 7 + 9 ⇒ (x + 3)2 = 16 ⇒ x + 3 = ±4 ⇒ x = -7 or 1
-10 = 6x - 16, or 16 - 10 = 6x, or x = 1.
None but it can be simplified to: 162x-468
x2 + 6x = 16=> x2 + 6x - 16 = 0=> x2 + 8x -2x - 16 = 0=> (x+8)(x-2) = 0=> x = -8 or x = 2So, the solutions of the quadratic equation x2 + 6x = 16 are -8 and 2.
-16 = 6x Swap: 6x = -16 Divide both sides by 6: x = -16/6 = -8/3 or -22/3 or -2.66...
2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
The quadratic equation will have two solutions.
x2 + 6x = 7 ⇒ x2 + 6x + 9 = 7 + 9 ⇒ (x + 3)2 = 16 ⇒ x + 3 = ±4 ⇒ x = -7 or 1
-10 = 6x - 16, or 16 - 10 = 6x, or x = 1.
6x-4 = 18 6x = 18+4 6x = 22 x = 22/6 = 3 and 2/3
None but it can be simplified to: 162x-468
-22
x2 - 6x - 16 = (x - 8)(x + 2)
-x2 + 6x + 16 = -(x2 - 6x - 16) = -(x - 8)(x + 2) = -(8 - x)(x + 2)
x^2+6x-16 (x+2)+(6x-16) x+8+x-16 (x+8)(x-2) here you go :)