(11, 1, 0) and (0, 1, 11) are the two possible solutions.
22
12 + 10 + 11 equals 33
There are two solutions for x: x=11 and x=-7
it equals 28
I suspect the answer depends on the value of t.
There is no solution. There is no number that can be put in place of 'x' that can make that statement true.
The two solutions are the conjugate complex numbers, +i*sqrt(11) and -i*sqrt(11), where i is the imaginary square root of -1.
(11, 1, 0) and (0, 1, 11) are the two possible solutions.
Since the highest power of 'x' in the equation is '1', there's one solution.
The solutions work out as: x = 52/11, y = 101/11 and x = -2, y = -11
107 divided by 12 equals 8 with a remainder of 11. There are many other possible solutions as well.
22
12 + 10 + 11 equals 33
There are two solutions for x: x=11 and x=-7
With difficulty because the discriminant of the quadratic equation is less than zero meaning it has no solutions
it equals 28