2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
2x2 + 15x + 25 = (2x + 5)(x + 5)
If you mean: 2x2+15x+25 then it is (2x+5)(x+5)
You are supposed to calculate the so-called discriminant, b2 - 4ac. If the result is positive, the equation has two real solutions; if it is zero, one real solution; if it is negative, no real solution (and two complex solutions). For this particular equation, a = 1, b = -10, and c = 25.
If: 11x+25 = 7x+15 then there is only one solution and it is x = -2.5
The quadratic equation will have two solutions.
2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
2x2 + 15x + 25 = (2x + 5)(x + 5)
If you mean: 2x2+15x+25 then it is (2x+5)(x+5)
You are supposed to calculate the so-called discriminant, b2 - 4ac. If the result is positive, the equation has two real solutions; if it is zero, one real solution; if it is negative, no real solution (and two complex solutions). For this particular equation, a = 1, b = -10, and c = 25.
If: 11x+25 = 7x+15 then there is only one solution and it is x = -2.5
-20
Two cases in which this can typically happen (there are others as well) are: 1. The equation includes a square. Example: x2 = 25; the solutions are 5 and -5. 2. The equation includes an absolute value. Example: |x| = 10; the solutions are 10 and -10.
x2 - 25 = 0 is x2 = 25 thus x = 5 or x = -5, only 2 real solutions
It is 5
you just add 6x+9x to get 15x then minus 25 from 18 to get -7 thus the answer will be 15x-7
25X + 30 = 15X subtract 15X from each side 25X - 15X + 30 = 15X - 15X 10X + 30 = 0 subtract 30 from each side 10X + 30 - 30 = 0 - 30 10X = -30 divide both sides integers by 10 (10/10)X = - 30/10 X = - 3 ----------------check in original equation 25(- 3) + 30 = 15(- 3) - 75 + 30 = - 45 - 45 = - 45 ----------------checks