To determine the number of solutions for the system of equations (x + 2y = 10) and (4y - 20 = 2x), we can rewrite the second equation as (2x - 4y + 20 = 0). Rearranging gives us (x = 2y + 10). Substituting this into the first equation leads to a consistent system, indicating that there is exactly one solution where the lines intersect. Thus, the system has one unique solution.
4y20 = 500 => y20 = 25 => y = 20√25 = 1.1746 approx Then x = 500 - y = 489.8254 (approx).
many solutions
1
many solutions
Two solutions and they are:- x = 0 and y = 3
4y20 = 500 => y20 = 25 => y = 20√25 = 1.1746 approx Then x = 500 - y = 489.8254 (approx).
many solutions
There are 120 solutions.
1
1 solution
many solutions
2
Two solutions and they are:- x = 0 and y = 3
One solution.
It has two equal solutions of 2
zero solutions. If you plot these two lines, you will see that they are parallel and do not intersect.
Only 1.