To determine the number of solutions for the equations (2yx = 2) and (-2x = 3), we can analyze them separately. The first equation can be rewritten as (yx = 1), which represents a hyperbola in the (xy)-plane and has infinitely many solutions for (y) given any non-zero (x). The second equation, (-2x = 3), simplifies to (x = -\frac{3}{2}), providing a single solution for (x). Thus, the two equations together yield infinitely many solutions for (y) based on the single solution for (x).
y=x^3
Without an equality sign the given expression is not an equation
3
Two solutions and they are:- x = 0 and y = 3
yx-3 is not an equation, and it has no graph.
To determine the number of solutions for the equations (2yx = 2) and (-2x = 3), we can analyze them separately. The first equation can be rewritten as (yx = 1), which represents a hyperbola in the (xy)-plane and has infinitely many solutions for (y) given any non-zero (x). The second equation, (-2x = 3), simplifies to (x = -\frac{3}{2}), providing a single solution for (x). Thus, the two equations together yield infinitely many solutions for (y) based on the single solution for (x).
The problem to solve is: xy+x+3y+3 Multiply y and x Multiply the y and x Multiply y and x The y just gets copied along. The x just gets copied along. The answer is yx yx x*y evaluates to yx x*y+x evaluates to yx+x Multiply y and 3 Multiply y and 1 The y just gets copied along. The answer is y y 3*y evaluates to 3y The answer is yx+x+3y x*y+x+3*y evaluates to yx+x+3y The answer is yx+x+3y+3 x*y+x+3*y+3 evaluates to yx+x+3y+3 ---- The final answer isyx+x+3y+3----
y=x^3
I don’t know
Without an equality sign the given expression is not an equation
3
This gives us the equations: n = xy = yx x != y (Note that for this example, the != stands for not equal to similar to some programming languages.) xy always equals yx due to the communtative property of multiplication. So there are actually an infinite number of answers. Some are given below: 6 = (2)(3) = (3)(2), 2 != 3 12 = (3)(4) = (4)(3), 3 != 4
If the highest degree of an equation is 3, then the equation must have 3 solutions. Solutions can be: 1) 3 real solutions 2) one real and two imaginary solutions.
1419.53 ml
2.7divided by 3 with solutions = 0.9
Two solutions and they are:- x = 0 and y = 3