Let's assume you mean a square table, 60 inches on each side. 60 inches is 5 feet (60/12). So a square table with a side of 5 feet would have an area of 25 sq. ft (5 x 5). Therefore, the number of tables n * 25 sq. ft/ table = 2000 sq. ft. so n= 2000/25 = 80.
Regard the problem as, 4 x n = 94 : then n = 94/4 = 23.5 ft
-53+n = -28 n = -28+53 n = 25
28 + N = 68 Subtract 28 from each side: N = 40
It looks like you are asking how many combinations of 6 numbers are there in the 28 numbers 1 through 28. This is known as the number of combinations of 28 things taken 6 at a time. The answer is 28!/(6!22!) (n! means n factorial, which is the product of all the integers from 1 to n). I get 376,740 if I haven't made an error in arithmetic.
If you mean "how many 3x5-inch cards cover 300 sq. ft": 1 card = 3*5 =15 sq. in. = 15/144 sq. ft. (12x12 = 144 in^2 = 1 ft^2) N cards *15/144 = 300 N = (300*144)/15 = 2880
For how long?
Let's assume you mean a square table, 60 inches on each side. 60 inches is 5 feet (60/12). So a square table with a side of 5 feet would have an area of 25 sq. ft (5 x 5). Therefore, the number of tables n * 25 sq. ft/ table = 2000 sq. ft. so n= 2000/25 = 80.
A perimeter is not enough to determine the area. A 4000 ft perimeter could be a circular shape with radius giving an area of 1,273,000 sq ft (approx) = 29.23 acres. It could be a 1000 ft * 1000 ft square with an area of 1,000,000 sq ft = 22.96 acres or a 500 ft * 1500 ft rectangle with an area of 750,000 sq ft = 17.22 acres or a 100 ft * 1900 ft rectangle with an area of 190,000 sq ft = 4.36 acres or a 10 ft * 1990 ft rectangle with an area of 19,900 sq ft = 0.46 acres or a 1 ft * 1999 ft rectangle with a n area of 1,999 sq ft = 0.05 acres or a 0.1 ft * 1999.9 ft etc. As you might guess from the above, by reducing one dimension the area of the parcel of land can be reduced without limit although the perimeter is left unchanged.
Regard the problem as, 4 x n = 94 : then n = 94/4 = 23.5 ft
It is any one of the infinitely many fractions of the form (28*n)/(70*n) where n is a non-zero integer or where 1/n is a common factor of 28 and 70.
3600 hectares in 36 sq kms.
-53+n = -28 n = -28+53 n = 25
If you assign the value N for width, the length would be N + 9. The area would then be: N(N + 9) = 630. This would be: N2 + 9N - 630 = 0. This can be factored into: (N + 30)(N - 21) = 0, and since you can't have negative feet, that leaves you with N = 21. Thus, the width is 21 and the length is 30.
28 + N = 68 Subtract 28 from each side: N = 40
It looks like you are asking how many combinations of 6 numbers are there in the 28 numbers 1 through 28. This is known as the number of combinations of 28 things taken 6 at a time. The answer is 28!/(6!22!) (n! means n factorial, which is the product of all the integers from 1 to n). I get 376,740 if I haven't made an error in arithmetic.
28