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The area of a rectangle that's 22-ft long and 6-ft wide is 132 square feet.
If 22 feet is the radius then area is pi x 22 x 22 square feet where pi = 3.1415 If 22 feet is the diameter then area is pi x11 x 11 square feet where pi = 3.1415
21-ft x 22-ft = 462 ft2
I assume you want the area of a triangle with side lengths 18 ft, 22 ft and 16 ft. Given the sides of a triangle, its area is given by: area = √(s(s - a)(s - b)(s - c)) Where s is the semi-perimeter, ie s = ½(a + b + c) or triangle with sides 18 ft, 22 ft 16 ft, area is: s = ½(18 + 22 + 16) ft = 28 ft → area = √(28(28 - 18)(28 - 22)(28 - 16)) ft² = √3360 ft² ≈ 57.97 ft²
The perimeter of a 22 ft square is 88 ft.