To calculate the number of tiles needed for a 500 square foot area using 16x16 inch tiles, first convert the tile size into square feet. Each 16x16 inch tile is 1.33 square feet (16 inches = 1.33 feet, so 1.33 x 1.33 = 1.78 square feet). Next, divide the total area (500 sq ft) by the area of one tile (1.78 sq ft): 500 ÷ 1.78 ≈ 280 tiles are needed. Always consider ordering extra tiles for cuts and future repairs.
297 16x16-inch tiles.
125 16-inch tiles.
Assuming you mean the tiles are 16 inches square - you would need 169 tiles.
141
First I would convert 16x16 inch tiles in feet 16x16 inch tiles = 1.25x1.25 feet tiles To calculate the square feet that one tile takes up multiply 1.25 x 1.25 1.25 x 1.25 = 1.5625 sq feet Now calculate 190/1.5625 to find the number of tiles that can fit in 190 square feet 190/1.5625 = 121.6 You will need 121-122 square tiles
297 16x16-inch tiles.
256
150 16x16" tiles; you'll have a small part of one tile left over.
125 16-inch tiles.
Assuming you mean the tiles are 16 inches square - you would need 169 tiles.
141
First I would convert 16x16 inch tiles in feet 16x16 inch tiles = 1.25x1.25 feet tiles To calculate the square feet that one tile takes up multiply 1.25 x 1.25 1.25 x 1.25 = 1.5625 sq feet Now calculate 190/1.5625 to find the number of tiles that can fit in 190 square feet 190/1.5625 = 121.6 You will need 121-122 square tiles
178 Tiles If the square footage is the actual room size you add 10% for wastee
Depends on how much overlap there is with neighboring tiles, and if you need part-tiles at the sides etc. At least 120 at a guess.
Each 16 inch tile is 1.78 square feet. You would need 169 tiles, plus some for spoilage.
You need 27 Box of 9 tiles
Well, darling, if each tile is 16x16 square feet, then you just need to divide the total area (150 square feet) by the area of one tile (16x16 square feet) to get your answer. So, 150 divided by 16x16 equals about 5.86 tiles. But since you can't have a fraction of a tile, you'll need to round up to 6 tiles to cover that 150 square feet.