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Are you asking for distinct 3-digit numbers? If so, there are 10 ways to pick the first digit, 9 ways to pick the second, and 8 to pick the third. Using the counting/multiplication principle, there are 10*9*8 = 720 3-permutations. Note that in this case the group 321 is considered different from the group 123.
If you're looking for an unordered grouping, then you'll need to divide out the ways in which the 3 digits selected can be arranged. Now we'll consider the group 321 the same as 123. A group of three things can be arranged in 6 ways, so we find 720/6 = 120 ways.
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How many four digit pins could begin with the number 0?
1000 because there are ten possibilities 0123456789 and there are four slots but the first slot has to be zero so it is 10 times 10 times 10 times 1
How many combinations of 16 numbers are there in 4 groups?
Assuming that the question is about4 groups of 4 numbers, andthe order of the groups does not matter.there are 2,627,625 combinations.The number is only 24 times as large is the order of the groups does, in fact matter. However, if the 4 groups can be of any size (provided their total is 16), the question goes beyond my ability - particularly at this time of the day!
How many 3 digit numbers can be made from 0123456789?
To form a three-digit number using the digits 0-9, the first digit cannot be 0 (as it would not be a three-digit number). Thus, the first digit can be any of the digits from 1 to 9 (9 options). The second and third digits can each be any digit from 0 to 9 (10 options each). Therefore, the total number of three-digit numbers is (9 \times 10 \times 10 = 900).
How do you rearrange this equation to make x the subject a times x-9 equals b?
ax-9 = b x = (b+9)/a
How many different combinations of numbers can you get from 1 to 36 in groups of 5 eg 2 5 34 8 4.?
If not using the same number twice: 36x35x34x33x32= 45,239,040 If allowed to use all numbers up to 5 times: 36x36x36x36x36=60,466,176
