To find the weight of sand in 1 acre at a depth of 10 feet, first calculate the volume. An acre is 43,560 square feet, so 1 acre at 10 feet deep has a volume of 435,600 cubic feet. Sand typically weighs about 100 pounds per cubic foot, so the total weight is approximately 43,560,000 pounds. Dividing by 2,000 gives about 21,780 tons of sand.
You need to mention how deep you want the sand to be
tweleve
57.6 cu ft
.617 Yards
(33.33)/(the number of cubic feet in each bag)
That depends on how deep the sand is.
1 acre is approx 4000 sq m8 ft is about 2.4 m.so 1 acre at 8 ft depth = 4000* 2.4= 9600 cu meter===========================1 acre = 43,560 square feetVolume = 43,560 x 8 = 348,480 cubic feet = 9,867.9 cubic meters (rounded)Note: That's the volume of 1 acre 8 feet deep, whether it's empty, or full of sand,mud, water, or old newspapers.
You need to mention how deep you want the sand to be
how deep?
You need to know how deep you want the sand.
tweleve
57.6 cu ft
.617 Yards
15745 cu-ft or 583 cu-yd of sand
(33.33)/(the number of cubic feet in each bag)
To many variables in question
An area 10 foot x 10 foot is 100 square feet. 100 cubic feet of sand would cover it with a one foot deep layer of sand. If the sand needs to be 6 inches deep, then 50 cubic feet are be needed, or 25 cubic feet if the sand is to be 3 inches thick.