3
Isosceles
triangle and trrapezium
Select any vertex and draw 2 lines to the two opposite vertices.
It is: 8-2 = 6 triangles
Isosceles
yes because you can draw a pentagon and devide it
it's 3 triangles
Pentagon
If the pentagon is a regular pentagon, then each of the central angles (formed by joinning the center with the vertices) is72⁰ (1/5 of 360⁰). So that 5 congruent isosceles triangle are formed, with base angles of 54⁰. If we draw the height, of these triangles (from the center to the sides of the pentagon), 10 congruent right triangles are formed. Let denote with: b the sides of the pentagon, and h the height. In one of the right triangles we have: tan 54⁰ = h/(b/2) tan 54⁰ = 2h/b 1.38 = 2h/b 2h = 1.38b h = (1.38/2)b h = .69b So that, h/b = .69b/b = .69
Isosceles
If you want it divided into five equal parts, draw a dot in the center of the pentagon, and draw a line form each vertex to the dot. You should now have five equal triangles.
33 triangles
triangle and trrapezium
Select any vertex and draw 2 lines to the two opposite vertices.
It is: 8-2 = 6 triangles
Isosceles
One possible way to divide a pentagon into five parts is (assuming this is a convex pentagon) to start by placing a dot directly in the center. Then, draw a 5 lines from that center dot connecting to the 5 points around the edge of the pentagon. You should now have 5 triangles instead of 1 pentagon.