33 triangles
3 triangles
You Can Get 6 triangles
A hexagon has 9 diagonals. Each vertex of a n-sided polygon can be connected to n - 3 others with diagonals. Thus n(n - 3) possible diagonals. However, when Vertex A is connected to vertex C, vertex C is also connected to vertex A, thus each diagonal is counted twice. Thus: number_of_diagonals = n(n - 3)/2 = 6(6-3)/2 = 6x3/2 = 9
There can be 14 lines in a seven side shape * * * * * That is the total number of diagonals from ALL vertices. Not what the question asked, though. From one vertex, there can be 4. One to every other vertex except for itself and one each on either side.
Find the midpoint of the two diagonals
If all of the diagonals are drawn from a vertex of an octagon, how many triangles are formed
Two triangles can be formed by the diagonals of one vertex of a four-sided polygon.
4 are formed
5 triangles are formed.
depends on what shape that vertex is in
1 triangle is formed.
There are 8
4
8
A 35-gon has 560 diagonals 0.5*(352-3*35) = 560
98
21