In a 100-sided polygon, if diagonals are drawn from one vertex, they connect to all non-adjacent vertices. A vertex connects to 97 other vertices (100 total vertices minus the 1 vertex itself and the 2 adjacent vertices). The number of triangles formed with the diagonals from that vertex is given by the formula for combinations, specifically ( \binom{97}{2} ), which equals 4,656 triangles.
Two triangles can be formed by the diagonals of one vertex of a four-sided polygon.
It is: 8-2 = 6 triangles
A hexagon can be divided into four triangles by drawing all of the diagonals from one vertex. Since a hexagon has six sides, drawing diagonals from one vertex creates three additional triangles, resulting in a total of four triangles (the original triangle formed by the vertex and two adjacent vertices, plus the three formed by the diagonals).
There are 8
A polygon with ( n ) sides can be divided into ( n - 2 ) triangles by drawing all the diagonals from one vertex. This is because each diagonal connects the chosen vertex to another vertex, forming a triangle with each adjacent pair of vertices. Therefore, for a polygon with ( n ) sides, you will create ( n - 2 ) triangles in total.
Two triangles can be formed by the diagonals of one vertex of a four-sided polygon.
98
21
98
It is: 8-2 = 6 triangles
If all of the diagonals are drawn from a vertex of an octagon, how many triangles are formed
5 triangles are formed.
depends on what shape that vertex is in
A hexagon can be divided into four triangles by drawing all of the diagonals from one vertex. Since a hexagon has six sides, drawing diagonals from one vertex creates three additional triangles, resulting in a total of four triangles (the original triangle formed by the vertex and two adjacent vertices, plus the three formed by the diagonals).
1 triangle is formed.
18 triangles
There are 8