128
Five people can stand in a line in 5! (5 factorial) different ways. This is calculated as 5 × 4 × 3 × 2 × 1, which equals 120. Therefore, there are 120 different arrangements for the 5 people in a line.
10 people can line up in (10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2) = 3,628,800 different ways.
24 ways
24
5! (5 factorial), which is 1 x 2 x 3 x 4 x 5.
4*3*2*1 = 24 ways.
There are n! (n factorial) ways that n people can stand in line. So six people can stand in line in: 1*2*3*4*5*6 = 720 different ways
10 people can line up in (10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2) = 3,628,800 different ways.
24 ways
24
5! (5 factorial), which is 1 x 2 x 3 x 4 x 5.
24 different ways.
Assuming that they are not all the same height: 0 This is because the shortest person in the line will have to have someone taller them than on at least one side of them. If they are all the same height: the number of ways that they could stand in a line is 7 x 6 x 5 x 4 x 3 x 2 x 1 = 7! = 5040
8x4=32
First place can be any of 6, second any of 5 etc. 6 x 5 x 4 x 3 x 2 = 720 different ways!
In a line in 6! = 6*5*4*3*2*1 = 720 ways.
In a straight line, 5! = 5*4*3*2*1 = 120 ways.